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Fynjy0 [20]
3 years ago
10

Kyle and Jenny both have pet rabbits. They wanted to see who had the fastest rabbit, so they each recorded data at their homes a

nd brought it's the results. Kyle rabbit went a total of 40 m in a time of one minute and 20 seconds. Jenny's rabbit went 30 m in one minute and 30 seconds. What was the velocity of Kyle's rabbit? What was the velocity of jennies rabbit? Whose rabbit was the fastest?
Physics
1 answer:
jekas [21]3 years ago
7 0

Answer:

v_kyle = 0.5 m/s

v_jennies = 0.333 m/s

Kyle's Rabbit was the fastest

Explanation:

For the velocity of Kyle's Rabbit:

d = distance covered = 40 m

t = time taken = (1 min)(60s/1 min) + 20 s = 80 s

v_{kyle} = \frac{d}{t} = \frac{40\ m}{80\ s}

<u>v_kyle = 0.5 m/s</u>

For the velocity of Jennies Rabbit:

d = distance covered = 30 m

t = time taken = (1 min)(60s/1 min) + 30 s = 90 s

v_{jennies} = \frac{d}{t} = \frac{30\ m}{90\ s}

<u>v_jennies = 0.333 m/s</u>

It is clear from the results that:

<u>Kyle's Rabbit was the fastest</u>

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Answer:

wrong statement :  Momentum is not conserved for a system of objects in a head-on collision.

Explanation:

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A stationary speed gun emits a microwave beam at 2.10*10^10Hz. It reflects off a car and returns 1030 Hz higher. What is the spe
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Answer: V = 15 m/s

Explanation:

As  stationary speed gun emits a microwave beam at 2.10*10^10Hz. It reflects off a car and returns 1030 Hz higher. The observed frequency the car will be experiencing will be addition of the two frequency. That is,

F = 2.1 × 10^10 + 1030 = 2.100000103×10^10Hz

Using doppler effect formula

F = C/ ( C - V) × f

Where

F = observed frequency

f = source frequency

C = speed of light = 3×10^8

V = speed of the car

Substitute all the parameters into the formula

2.100000103×10^10 = 3×10^8/(3×10^8 -V) × 2.1×10^10

2.100000103×10^10/2.1×10^10 = 3×108/(3×10^8 - V)

1.000000049 = 3×10^8/(3×10^8 - V)

Cross multiply

300000014.7 - 1.000000049V = 3×10^8

Collect the like terms

1.000000049V = 14.71429

Make V the subject of formula

V = 14.71429/1.000000049

V = 14.7 m/s

The speed of the car is 15 m/s approximately.

8 0
3 years ago
A 3-kg rock is thrown upward with a force of 200 N at a location where the local gravitational acceleration is 9.79 m/s2 . Deter
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Answer: 56.87m/s^{2}

Explanation:

If we make an analysis of the net force F_{net} of the rock that was thrown upwards, we will have the following:

F_{net}=F_{up}-W  (1)

Where:

F_{up}=200N is the force with which the rock was thrown

W is the weight of the rock

Being the weight the relation between the mass m=3kg of the rock and the acceleration due gravity g=9.79m/s^{2} :

W=m.g=(3kg)(9.79m/s^{2}) (2)

W=29.37 N (3)

Substituting (3) in (1):

F_{net}=200N-29.37 N  (4)

F_{net}=170.63 N  (5) This is the net Force on the rock

On the other hand, we know this force is equal to the multiplication of the mass with the acceleration, according to Newton's 2nd Law:

F_{net}=m.a  (6)

Finding the acceleration a:

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Finally:

a=56.87m/s^{2}

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Answer:

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