1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dlinn [17]
3 years ago
14

Amanda spent 2/5 of her time after school doing homework and ¼ of her remaining time riding her bike. If she rode her bike for 4

5 minutes in a week, how much time did she devote to homework in the same week?
Physics
1 answer:
Doss [256]3 years ago
6 0

Answer:120 min

Explanation:

Given

Amanda  spent \frac{2}{5} of her time after school doing Home work

And \frac{1}{4} of her remaining  time riding her bike

It is given that she rode her bike for 45 minutes in a week

Let t be the time after school

therefore Amanda spend \frac{2t}{5} in home work and  \frac{3t}{5} time is left

From remaining \frac{3t}{5} time she spends \frac{1}{4} time riding her bike

therefore \frac{3t}{5}\times \frac{1}{4}=45

thus t=300 min

therefore time  spent on home work is \frac{2}{5}\times 300=120 min

You might be interested in
A 0.5 kg cheeseburger is lobbed at a particularly unhappy customer with a force of 10 N.
aleksley [76]
The acceleration that the cheeseburger experienced is 20 m/s^2.
6 0
3 years ago
The radial velocity method preferentially detects: Choose one: A. all of the above described planets equally well. B. small plan
Zina [86]

The radial velocity method preferentially detects large planets close to the central star

  • what is the Radial velocity:

The radial velocity technique is able to detect planets around low-mass stars, such as M-type (red dwarf) stars.

This is due to the fact that low mass stars are more affected by the gravitational tug of planets.

When a planet orbits around a star, the star wobbles a little.

From this, we can determine the mass of the planet and its distance from the star.

hence we can say that,

option D is correct.

The radial velocity method preferentially detects large planets close to the central star

Learn more about radial velocity here:

<u>brainly.com/question/13117597</u>

#SPJ4

5 0
2 years ago
A small metal object is tied to the end of a string and whirled round a circular path of radius 30cm. The object makes 20 oscill
LUCKY_DIMON [66]

Answer:

(i) The angular speed of the small metal object is 25.133 rad/s

(ii) The linear speed of the small metal object is 7.54 m/s.

Explanation:

Given;

radius of the circular path, r = 30 cm = 0.3 m

number of revolutions, n = 20

time of motion, t = 5 s

(i) The angular speed of the small metal object is calculated as;

\omega = \frac{20 \ rev}{5 \ s} \times \frac{2 \pi \ rad}{1 \ rev} = \frac{40\pi \ rad}{5 \ s} = 8\pi \ rad/s = 25.133 \ rad/s

(ii) The linear speed of the small metal object is calculated as;

v = \omega r\\\\v = 25.133 \ rad/s \ \times \ 0.3 \ m\\\\v = 7.54 \ m/s

6 0
3 years ago
A hotel elevator ascends 200m with maximum speed of 5m/s. Its acceleration and deceleration both have a magnitude of 1.0m/s2. Pa
ValentinkaMS [17]

Answer:

45 s .

Explanation:

The accelerator will first accelerate , then move with uniform velocity and at last it will decelerate to rest .

displacement s = ?

acceleration a = 1 m /s²

Final speed v = 5 m/s

initial speed u = 0

v² = u² + 2as

5² = 0 + 2 x 1 x s

s = 12.5  m

B)  Let time of acceleration or deceleration be t

v = u + a t

5 = 0 + 1 t

t = 5 s

Similarly displacement during deceleration = 12.5 m

Total distance during uniform motion = 200 - ( 12.5 + 12.5 ) =  175 m .

velocity of uniform motion = 5 m /s

time during which there was uniform velocity = 175 / 5 = 35 s

Total time = 5 + 35 + 5 = 45 s .

4 0
3 years ago
If a nearsighted person has a far point df that is 3.50m from the eye, what is the focal length f1 of the contact lenses that th
olga55 [171]

Answer:

f1= -350cm or -3.5m

f2= 22.1cm or 0.221m

Explanation:

A person is nearsighted when the person's far point is less than infinity. A diverging lens is normally used to correct this eye defect. A diverging lens has a negative focal length as seen in the solution attached.

Farsightedness is when a person's near point is farther than 25cm. This eye defect is corrected using a converging lens. The focal length of a converging lens is positive. This is evident in the solution attached. The near point is also referred to as the least distance of distinct vision.

3 0
3 years ago
Other questions:
  • When a 100-Ω resistor is connected across the terminals of a battery of emf ε and internal resistance r, the battery delivers 0.
    13·1 answer
  • Which term describes the amount of charge that passes a point in a circuit<br> each second?
    12·2 answers
  • Suppose that she pushes on the sphere tangent to its surface with a steady force of F = 60 N and that the pressured water provid
    10·1 answer
  • A rigid tank initially contains 1.4 kg saturated liquid water at 200◦C. At this state, 25 percent of the volumeis occupied by wa
    14·1 answer
  • A water-balloon launcher with mass 5 kg fires a 1 kg balloon with a velocity of
    13·1 answer
  • 3. What are the two types of mixtures?
    14·1 answer
  • Endocrine system immune response
    13·1 answer
  • What is the correct answer?
    5·2 answers
  • PLEASE HELP WITH EXPLANATION! I WILL GIVE YOU BRAINLIEST!
    11·1 answer
  • 3000 N is exerted for 4.0 seconds on a 9500 kg object.<br><br> What is the change in momentum?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!