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ankoles [38]
3 years ago
5

What is globalization? A) an organization of people competing against each other in physical activities B) learning about belief

s and characteristics of a particular social, ethnic, or age group C) the interaction and integration among the people, companies, and governments of different nations D)the strategy of positioning yourself to be successful against teams from other countries
Physics
2 answers:
Serhud [2]3 years ago
6 0
I think it is C but I am not for sure
SOVA2 [1]3 years ago
3 0
Globalization would be c

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What is the difference between direct current and alternating current?
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In a direct current, the electric charge, or current, only flows in one direction. In an alternating current, the electric charge changes periodically.  
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3 years ago
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Delilah does 170 Joules of work in 30 seconds. Adam does 260 Joules of work in 20 seconds. Who was more powerful?​
sp2606 [1]

Power = \frac{Work}{Time}

Delilah: 170J/30s = 5.66 W

Adam: 260J/20s = 13 W

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3 years ago
A proposed ocean thermal-energy conversion (OTEC) system is a heat engine that would operate between warm water (16°C) at the oc
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Answer:

3.46 %

Explanation:

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And the warm temperature of water that is T_h=16^{\circ}C=16+273=289\ K

The maximum possible efficiency is given by \eta =1-\frac{T_c}{T_h}

So maximum efficiency \eta =1-\frac{T_c}{T_h}=1-\frac{279}{289}=0.0346=3.46 %

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2 years ago
12. By convention (agreement of the scientific community for consistency)
Reptile [31]

Answer:

. always start on the north pole and terminate (end) on the South Pole

Explanation:

4 0
3 years ago
Hi im a little stuck on this question that came from my textbook in class it got a little confusing for me because i really dont
koban [17]

Consult the attached free body diagram.

By Newton's second law, the net force on the crate acting parallel to the surface is

∑ F[para] = (370 N) cos(-20°) - f = 0

(this is the x-component of the resultant force)

where

• (370 N) cos(-20°) = magnitude of the horizontal component of the pushing force

• f = magnitude of kinetic friction

The crate is moving at a constant speed and thus not accelerating, so the crate is in equilibrium.

Solve for f :

f = (370 N) cos(-20°) ≈ 347.686 N

The net force acting perpendicular to the surface is

∑ F[perp] = n - 1480 N - (370 N) sin(-20°) = 0

(this is the y-component of the resultant force)

where

• n = magnitude of normal force

• 1480 N = weight of the crate

• (370 N) sin(-20°) = magnitude of the vertical component of push

The crate doesn't move up or down, so it's also in equilibrium in this direction.

Solve for n :

n = 1480 N + (370 N) sin(-20°) ≈ 1606.55 N ≈ 1610 N

Then the coefficient of kinetic friction is µ such that

f = µn   ⇒   µ = f/n ≈ 0.216

7 0
2 years ago
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