Answer:
Explanation:
Take sum of torques at the point the step touches the wheel, that eliminates two torques
Σ
Since we are looking for when the wheel just starts to rise up N-> 0 so no torque due to normal force
The perpendicular lever arm for the F force is R-h
And the T of gravity according to the image
Σ
Answer:
5.24 m/s
Explanation:
So for the rod to be able to rise upward to the straight up position, the kinetic energy caused by linear speed v0 must be just enough to convert into the potential energy.
Since the rod is uniform in mass, we can treat the body as 1 point, at its center of mass, or geometric center, aka 0.35 / 2 = 0.175 m from the pivot.
For the rod to swing from bottom to top, the center must have moved a distance of h = 0.175 * 2 = 0.35 m, vertically speaking.
Since we neglect friction and air resistance, according to the law of energy conservation then:
Where v is the speed at the center of mass, g = 9.81 m/s2 is the gravitational acceleration, and m is the mass. We can divide both sides by m
As this is only the speed at the center of mass, the speed at the bottom end would be different, to calculate this, we need to find the common angular speed:
Where r is the rotation radius, or the distance from pivot point to the center of mass
Where R is the distance from the pivot to the bottom end of the rod
Answer:
Coil 2 have 235 loops
Explanation:
Given
The number of loops in coil 1 is n ₁= 159
The emf induced in coil 1 is ε ₁ = 2.78 V
The emf induced in coil 2 is ε ₂ = 4.11 V
Let
n ₂ is the number of loops in coil 2.
Given, the emf in a single loop in two coils are same. That is,
ϕ ₁/n ₁= ϕ ₂ n ₂⟹ 2.78/159 = 4.11/ n ₂
n₂=
n₂=235
Therefore, the coil 2 has n ₂= 235 loops.