We need to use rational root theorem to find out roots here.
The rational root theorem states that if p(x) is a polynomial with integer coefficients and if
is a zero of p(x) then p is a factor of constant term and q is a factor of leasing term coefficient.
Here factors of constant term are 1,2,3,4,6,8,12,24,-1,-2,-3,-4,-6,-8,-12, and -24.
And factors of leading coefficient is -1,1.
Hence possible roots may be -1,1,-2,2,-3,3,-4,4,-6,6,-8,8,-12,12,-24 and 24.
Let us plugin these in f(x) to find zeroes.
![f(-1)=(-1)^{4}+10(-1)^{3}+35(-1)^{2}+50(-1)+24 =1-10+35-50+24=0](https://tex.z-dn.net/?f=f%28-1%29%3D%28-1%29%5E%7B4%7D%2B10%28-1%29%5E%7B3%7D%2B35%28-1%29%5E%7B2%7D%2B50%28-1%29%2B24%20%3D1-10%2B35-50%2B24%3D0)
Hence x=-1 is a zero which means x-(-1)=x+1 is a factor.
Let us use synthetic division to find quotient.
-1 | 1 10 35 50 24
<u>| 0 -1 -9 -26 -24</u>
<u> 1 9 26 24 0</u>
Hence quotient is ![x^{3} +9x^{2} +26x+24](https://tex.z-dn.net/?f=x%5E%7B3%7D%20%2B9x%5E%7B2%7D%20%2B26x%2B24)
Since all coefficients are positive, root must be negative. Let's plugin all remaining negative numbers in the quotient.
![(-2)^{3}+9(-2)^{2}+26(-2)+24 = 0](https://tex.z-dn.net/?f=%28-2%29%5E%7B3%7D%2B9%28-2%29%5E%7B2%7D%2B26%28-2%29%2B24%20%3D%200)
Hence x+2 is another factor.
Let us find quotient again using synthetic division.
-2 | 1 9 26 24
<u>| 0 -2 -14 -24</u>
<u> 1 7 12 0</u>
Hence quotient is ![x^{2} +7x+12](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B7x%2B12)
Again we got quotient with all positive coefficients, let us plugin remaining negative numbers from rational root theorem.
![(-3)^{2}+7(-3)+12=-9-21+12=0](https://tex.z-dn.net/?f=%28-3%29%5E%7B2%7D%2B7%28-3%29%2B12%3D-9-21%2B12%3D0)
Hence x+3 is also a factor.
Let us find quotient using synthetic division.
-3 | 1 7 12
<u>| 0 -3 -12</u>
<u> 1 4 0</u>
Hence quotient is x+4.
So, ![f(x)=x^{4}+10x^{3}+35x^{2}+50x+24 =(x+1)(x+2)(x+3)(x+4)](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B4%7D%2B10x%5E%7B3%7D%2B35x%5E%7B2%7D%2B50x%2B24%20%3D%28x%2B1%29%28x%2B2%29%28x%2B3%29%28x%2B4%29)
Please have a look at the graph attached.