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galben [10]
3 years ago
13

Jake’s bank offers him an account with 3% interest, compounded

Mathematics
1 answer:
defon3 years ago
6 0
\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{compounded amount}\\
P=\textit{original amount deposited}\to &\$1320\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, meaning once}
\end{array}\to &1\\

t=years\to &5
\end{cases}

he'll be earning in interest, the difference from A to P, or A - P
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h(x)= \dfrac{1}{8} x^3 - x^2h(x)= 8 1 ​ x 3 −x 2 h, left parenthesis, x, right parenthesis, equals, start fraction, 1, divided b
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Answer:

\dfrac{1}{2}

Step-by-step explanation:

Given the function h(x)=\dfrac{1}{8}x^3-x^2

The average rate of change of the function h(x) over the interval a\le x\le b can be calculated using formula

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\dfrac{h(2)-h(-2)}{2-(-2)}\\ \\=\dfrac{(\frac{1}{8}\cdot 2^3-2^2)-(\frac{1}{8}\cdot (-2)^3-(-2)^2)}{4}\\ \\=\dfrac{(1-4)-(-1-4)}{4}\\ \\=\dfrac{-3+5}{4}\\ \\=\dfrac{2}{4}\\ \\=\dfrac{1}{2}

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natta225 [31]

Answer:

B. -2 1/2 +3 1/4 = 3/4

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the starting point is -2 1/2, they added 3 1/4, and the ending point is 3/4.

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