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Marina86 [1]
4 years ago
6

Paul is taking inventory of unsold ladies’ dresses from last month. The following matrix shows how many of each dress were left

in red, blue, white, and green. The matrix below shows the new stock of the same color dresses that arrived in the store today. Which matrix shows the total number of dresses of each color and size that Paul has in stock before any sales were made today?

Mathematics
2 answers:
Korvikt [17]4 years ago
7 0

Answer:

Step-by-step explanation: A

Allisa [31]4 years ago
5 0

Answer:

A

Step-by-step explanation:

Just add both matrices

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Pls click on me I need help( I’m trying to show my mom I’m smart
galben [10]

Answer:

30

Step-by-step explanation:

30 because 15/20=30/40

8 0
3 years ago
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There are 157 college students interviewed about their work schedules. 85 of them work during the day. 43 of them work nightshif
stepan [7]

Step-by-step explanation:

No of students work during day shift = 85

No of students work during night shift = 43

No of students working both shift = 28

So first we will divide 28 by 2 = 14

Then it means there were 14 students working in day shift and 14 students working in night shift

Total number of students work during day shift = 85 + 14 = 99

7 0
3 years ago
− 2 3 y − 3 5 x + 2 9 − 4 5 x + 1 3 y Let x = 5 and y = 3. − 2 3 (3) − 3 5 (5) + 2 9 − 4 5 (5) + 1 3 (3) = −2 − 3 + 2 9 − 4 + 1
Ivahew [28]

Answer:

-16 :)

Step-by-step explanation:

8 0
3 years ago
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You have 8,640 grams of a radioactive kind of cesium. If its half-life is 30 years, how much
Vikki [24]

The mass of cesium left afer 120 years if the original mass of cesium is 8640 with an half-life of 30 years,  is 540 grams.

<h3>What is half-life?</h3>

This can be defined as the time taken for half the amount of a radioactive substance to decay.

To calculate the amount of cesium left after 120 years, we use the formua below.

Formula:

  • R' = R/(2^{T/t})............. Equation 1

Where:

  • R = Original amount of Cesium
  • R' = New amount of cesium
  • T = Total time
  • t = Half-life

From the question,

Given:

  • R = 8640
  • T = 120 years
  • t = 30 years

Substitute these values into equation 1

  • R' = 8640/(2^{120/30})
  • R' = 8640/2^{4}
  • R' = 8640/16
  • R' = 540 grams.

Hence, The mass of cesium left afer 120 years is 540 grams.

Learn more about half-life here: brainly.com/question/25750315

4 0
2 years ago
Simplify 2a^2b^3 (4a^2 + 3ab^2 - ab) =?
stellarik [79]

The correct answer is D.D. 8a^4b^3 + 6a^3b^5 - 2a^3b^4

You can tell this by the lead term alone. When you mutliply the term outside to the lead term, D is the only one that has that term.

2a^2b^3*4a^2 = 8a^4b^3

D. 8a^4b^3 + 6a^3b^5 - 2a^3b^4

7 0
3 years ago
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