The finagling in the hole
The complete question is shown in the image attached to this answer.
Answer:
C
Explanation:
Let us quickly remember that the EMF of a cell under non standard conditions in given by the Nernst equation.
This equation states that;
E = E°cell - 0.592/n log Q
Where
E = EMF under non standard conditions
E°cell= standard EMF of the cell
n = number of electrons transferred
Q = reaction quotient
If the reaction quotient is greater than 1 then cell potential is less than the standard cell potential.
The cell that generates the lowest cell potential is the cell depicted in option C because Q has the greatest positive value(Q<1).
The question is incomplete. Complete question is attached below:
...........................................................................................................................
Answer:
Given: conc. of HBr = 1.4 M
Volume of HBr = 15.4 mL
Volume of KOH = 22.10 mL
We know that, M1V1 = M2V2
(HBr) (KOH)
Therefore, M2 = M1V1/V2
= 1.4 X 15.4/22.10
= 0.9756 M
Concentration of KOH is 0.9756 M.
<span><u><em>Answer:</em></u>
combustion reaction
<u><em>Explanation:</em></u>
In chemistry, a <u>combustion reaction</u> is defined as a reaction between an oxidant and any compound that leads to the production of another compound along with a huge amount of heat.
<u>Now, let's check the reaction given:</u>
C</span>₃H₈<span> + 5 O</span>₂<span> --> 3 CO</span>₂<span> + 4 H</span>₂O<span>
<u>The oxidant</u> is oxygen gas
<u>The compound reacting</u> is propane
<u>The compound produced</u> is carbon dioxide along with water vapor and heat
Therefore, the given reaction is a combustion reaction
Hope this helps :)</span>