Answer:
It would be higher than expected.
Explanation:
Respiration quotient (RQ) may be defined as the quantity used for the representation of the basal metabolic rate. This mainly depends on the amount of the carbon dioxide.
The respiratory quotient represents the ratio of carbon dioxide eliminated with the amount of the oxygen consumed. During stress condition, the oxygen consumption of our body increase and more carbon dioxide is exhale out from the body. This will increase the RQ.
Thus, the answer is RQ will be higher than expected.
Tris (as a pure compound normally supplied) is a base and its aqueous solutions are alcaline. It is not a buffer sensu stricto. To accumulate a buffering ability it sould be in equilibrium with the corresponding acid which is the protonated structure of Tris.
<h3>Is Tris damaging to humans?</h3>
The following acute (short-term) fitness consequences can also occur straight away or rapidly after publicity to Tris (2,3- Dibromopropyl) Phosphate: * Contact can irritate the pores and skin and eyes. * Tris (2,3-Dibromopropyl) Phosphate is a PROBABLE CARCINOGEN in humans.
<h3>Is Tris base toxic?</h3>
tris(hydroxymethyl)aminomethane
Potential Adverse human fitness effects and signs : Practically non-toxic. Non-toxic if swallowed (LD50 oral, rat > 5000 mg/kg). Non-toxic in contact with skin (LD50 skin> 5000 mg/kg). Not irritant to skin.
Learn more about TRIS here:
<h3>
brainly.com/question/27390164</h3><h3 /><h3>#SPJ4</h3>
The reaction for the combustion of methane can be expressed as follows.
CH4 + 2O2 --> CO2 + 2H2O
We solve first for the amount of carbon dioxide in moles by dividing the given volume by 22.4L which is the volume of 1 mole of gas at STP.
moles of CO2 = (5.6 L) / (22.4 L/1 mole)
moles of CO2 = 0.25 moles
Then, we can see that every mole of carbon dioxide will need 1 mole of methane
moles methane = (0.25 moles CO2) x (1 moles O2/1 mole CO2)
= 0.25 moles CH4
Then, multiply this by the molar mass of methane which is 16 g/mole. Thus, the answer is 4 grams methane.
