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3 years ago

What is the net force on a ball that falls downward?

1 answer:

6 0

There's no way to tell without knowing the downward acceleration of the ball.

For example, if it's falling at a constant speed, then the net vertical force on it is zero, and we still don't know anything about the net horizontal force.

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A circular-motion addict of mass 80 kg rides a Ferris wheel around in a vertical circle of radius 10 m at a constant speed of 6.

bekas [8.4K]

Answer with Explanation:

We are given that

Mass=80 kg

Radius,r=10 m

Speed,v=6.1 m/s

a.Time period,T= $\frac{2\pi r}{v}=\frac{2\pi\times 10}{6.1}=10.3 s$

b. $F_N=mg-\frac{mv^2}{r}$

Substitute the values

$F_N=80\times 9.8-\frac{80\times(6.1)^2}{10}=486 N$

c. $F_N=mg+\frac{mv^2}{r}$

Substitute the values

$F_N=80\times 9.8+\frac{80\times (6.1)^2}{10}=1081.7 N$

7 0

3 years ago

Over 4 seconds, a car's momentum decreases by 1000 kg m/s how much force did it take to make this happen?

kotykmax [81]

Answer:

250N

Explanation:

Given parameters:

Time = 4s

Momentum = 1000kgm/s

Unknown:

Force = ?

Solution:

To solve this problem, we use Newton's second law of motion;

Ft = Momentum

F is the force

t is the time

So;

F x 4 = 1000kgm/s

F = 250N

6 0

3 years ago

Calculat the acceleration of a person at latitude<br> 40degreesowing to the rotation of the earth.

beks73 [17]

Answer:

acceleration of person = 9.77 m/s²

Explanation:

given data

latitude = 40 degree

to find out

Calculate the acceleration of a person

solution

we know that here 40 degree = 0.698 rad

acceleration of person = g - ω²R ...............1

and 1 rotation complete in 24 hours = 360 degree

here g is 9.81

so we know Earth angular speed ω = 7.27 × $10^{-5}$ rad/s and R is earth radius that is 6.37 × $10^{6}$ m

put here value in equation 1 we get

acceleration of person = g - ω²R

acceleration of person = 9.81 - (7.27 × $10^{-5}$ )² × 6.37 × $10^{6}$

acceleration of person = 9.77 m/s²

6 0

4 years ago

our 3.80-kg physics book is placed next to you on the horizontal seat of your car. The coefficient of static friction between th

gtnhenbr [62]

Answer:

Explanation:

Maximum force of friction possible = μmg

= .65 x 3.8 x 9.8

= 24.2 N

u = 72 x 1000 / 60 x 60

= 20 m /s

v² = u² - 2as

a = 20 x 20 / (2 x 30)

= 6.67 m / s²

force acting on it

= 3.8 x 6.67

= 25.346 N

Friction force possible is less .

So friction will not be able to prevent its slippage

It will slip off .

4 0

3 years ago

Which particles are heavy and which are light

VashaNatasha [74]

Answer:

Protons and neutrons are heavy, Electrons are extremely light

Explanation:

Protons and neutrons are heavier than electrons and reside in the nucleus at the center of the atom. Electrons are extremely lightweight and exist in a cloud orbiting the nucleus.

3 0

3 years ago

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