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4 years ago

Why are dispersion forces weaker than dipole

Physics

1 answer:

vazorg [7]4 years ago

5 0

One is temporary one is permanent

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How does vapor release energy into the atmosphere

Oduvanchick [21]

I would say a because i just had this

4 0

3 years ago

Read 2 more answers

Please help me!

sergeinik [125]

C. The Densities are equal.

<h3>What is density?</h3>

Density is mass per unit volume or mass of a unit volume of a material substance.

If m1, V1 and D1 = mass, volume and density respectively of ball C

m2, V2 and D2 = mass, volume and density respectively of ball D

According to the Question ,

$V_{1} = 3V_{2} , m_{2} = \frac{1}{3} (m_{1} ) \\ \\= m_{1} = 3m_{2}$

Therefore,

$\frac{D_{1} }{D_{2} } = (\frac{m_{1} }{V_{1} } )* (\frac{m_{2} }{V_{2} } )\\ \\= (\frac{3m_{2} }{3V_{2} })*(\frac{V_{2} }{m_{2} }) \\\\= 1$

Hence, D1 = D2

Learn more about density here:brainly.com/question/15164682

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6 0

3 years ago

Hello please help i’ll give brainliest

AlekseyPX

Answer:

Oceanic crust moves easly. Continental crust does not move

8 0

3 years ago

A force of 34.5 newtons is applied to an object at an angle of 45 º with the horizontal. What is the force acting on the object

ddd [48]

The horizontal component of the force is 34.5 cos(45) = 24.4 newtons

The vertical component of the force is 34.5 sin(45) = 24.4 newtons

6 0

4 years ago

A certain freely falling object, released from rest, requires 1.95 s to travel the last 23.5 m before it hits the ground. (a) Fi

Ratling [72]

Answer:

(a). The velocity of the object is -2.496 m/s.

(b). The total distance of the object travels during the fall is 23.80 m.

Explanation:

Given that,

Time = 1.95 s

Distance = 23.5 m

(a). We need to calculate the velocity

Using equation of motion

$s = ut+\dfrac{1}{2}gt^2$

Put the value into the formula

$-23.5=u\times1.95+\dfrac{1}{2}\times(-9.8)\times(1.95)^2$

$u=\dfrac{-23.5+4.9\times(1.95)^2}{1.95}$

$u=-2.496\ m/s$

(b). We need to calculate the total distance the object travels during the fall

Using equation of motion

$v = u+gt$

Put the value in the equation

$-2.496=0-9.8\times t$

$t =\dfrac{2.496}{9.8}$

$t=0.254\ sec$

The total time is

$t'=t+1.95$

$t'=0.254+1.95$

$t'=2.204\ sec$

We need to calculate the distance

Using equation of motion

$s = ut+\dfrac{1}{2}gt^2$

Put the value into the formula

$s=0+\dfrac{1}{2}\times9.8\times(2.204)^2$

$s=23.80\ m$

Hence, (a). The velocity of the object is -2.496 m/s.

(b). The total distance of the object travels during the fall is 23.80 m.

4 0

3 years ago