Why are dispersion forces weaker than dipole
1 answer:
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Answer:
<h2>a) t = 4</h2>Explanation:
In projectile the time taken by an object to reach its maximum height is the maximum time (tmax).
tmax = Usin/g
U = velocity of the ball
= angle of projection = 90° (vertical velocity)
g = acceleration due to gravity = 9.8m/s²
tmax = Usin90°/9.8
tmax = U/9.8
T the maximum height U = Uy = 39.2 m/s²
tmax = 39.2/9.8
tmax = 4secs
To calculate the time at which the ball will have an horizontal velocity, we will use the same formula but will be 0° in this case
If Ux = Ucos
8 = Ucos0
U = 8m/s
Since t = Usin/g
t = 8sin0/9.8
t = 0sec
Answer:
1)
2)
Explanation:
Given:
- mass of heavier student,
- mass of lighter student,
- velocity of the heavier student after the mutual push,
1)
Since they push each other and we are neglecting any friction that means we can consider this as a perfectly elastic collision. So the momentum of the two bodies will be equal and in opposite direction.
Since momentum is a vector quantity so the total momentum of the system as a whole will be zero.
2)
<u>From the condition of elastic collision:</u>