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3 years ago

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A skier descends a mountain at an angle of 35.0º to the horizontal. If the mountain is 235 m long, what are the horizontal and v

ertical components of the skier's displacement? (Use trigonometry to solve.) x = y = .

2 answers:

Masja [62]3 years ago

7 0

Total displacement along the length of mountain is given as

L = 235 m

angle of mountain with horizontal = 35 degree

now we will have horizontal displacement as

x = L cos35

x = 235 cos35 = 192.5 m

similarly for vertical displacement we can say

y = L sin35

y = 235 sin35 = 134.8 m

Sonja [21]3 years ago

5 0

Answer:

x = 193 m

y = 135 m

Explanation:

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The acceleration of the baseball is:
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Replacing the numbers, we get
$a= \frac{30 m/s-0m/s}{0.5 s}=60 m/s^2$
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3 years ago

a 200 kg crate is pushed horizontally with a force of 700 N. If the coefficient of friction is 0.2 calculate the acceleration of

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Answer:

$a=1.54\ m/s^2$

Explanation:

<u>Net Force</u>

The Second Newton's law states that an object acquires acceleration when an external unbalanced net force is applied to it.

That acceleration is proportional to the net force and inversely proportional to the mass of the object.

It can be expressed with the formula:

$\displaystyle a=\frac{F_n}{m}$

Where

Fn = Net force

m = mass

The m=200 kg crate is pushed horizontally with a force Fa=700 N. The friction force opposes motion and a horizontal net force appears causing the acceleration.

The forces on the vertical direction are in balance since the crate does not accelerate in that direction, thus the weight and the normal force are equal:

N = W = mg

The friction force can be calculated by using the coefficient of friction μ:

$F_r=\mu N$

Calculating the normal force:

N = 200 * 9.8 = 1,960 N

The friction force is:

$F_r=0.2*1,960$

$F_r=392\ N$

The horizontal net force is:

$F_n = F_a-F_r=700\ N - 392\ N$

$F_n = 308\ N$

Finally, the acceleration is computed:

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3 years ago

At an accident scene on a level road, investigators measure a car’s skid mark to be 88 m long. The accident occurred on a rainy

Oduvanchick [21]

Answer:

The the speed of the car is 26.91 m/s.

Explanation:

Given that,

distance d = 88 m

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We need to calculate the the speed of the car

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work done = change in kinetic energy

$W=\Delta K.E$

$\mu\ mg\times d=\dfrac{1}{2}mv^2$

$v^2=2\mu g d$

Put the value into the formula

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3 years ago

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Answer:

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3 years ago

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Answer:

The correct answer is option B)

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Considering the given question as -

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Let ,

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$r_{e}$ : Distance of satellite from earth

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Given that $r_{e}$ = $r_{m}$

Let $r_{e}$ = $r_{m}$ =r

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4 years ago