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Korvikt [17]
3 years ago
12

A skier descends a mountain at an angle of 35.0º to the horizontal. If the mountain is 235 m long, what are the horizontal and v

ertical components of the skier's displacement? (Use trigonometry to solve.) x = y = .
Physics
2 answers:
Masja [62]3 years ago
7 0

Total displacement along the length of mountain is given as

L = 235 m

angle of mountain with horizontal = 35 degree

now we will have horizontal displacement as

x = L cos35

x = 235 cos35 = 192.5 m

similarly for vertical displacement we can say

y = L sin35

y = 235 sin35 = 134.8 m

Sonja [21]3 years ago
5 0

Answer:

x  = 193 m

y = 135 m

Explanation:

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3 years ago
1. A boy walk 140 m due north, 85 m due east, 35 m due southeast, 38 m due west and then 19 m due northwest. Calculate the displ
Dima020 [189]

Answer:

141 m at 65.6° N of E

Explanation:

Let E be along the positive x axis of a unit circle

N = 90°

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SE = -45°

W = 180°

NW = 135°

east displacement

x = 140cos90 + 85cos0 + 35cos-45 + 38cos180 + 19cos135 = 58.313708... m

north displacement

y = 140sin90 + 85sin0 + 35sin-45 + 38sin180 + 19sin135 = 128.6862915... m

d = √(128.6862915² + 58.313708²) = 141.28216525... m

tanθ = 128.6862915 / 58.313708

θ = 65.622521...

7 0
3 years ago
Which of the following is an example of matter
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For the first one, leaves is matter.
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8 0
3 years ago
Read 2 more answers
If the net force acting on an object is 100 N to the left, Are the forces unbalanced or balanced?
hodyreva [135]

Answer:

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8 0
3 years ago
A pendulum has a mass of 1.5 kg and starts at a height of 0.4 m. If it is released from rest, how fast is it going when it reach
ella [17]

Answer:

A. 2.8 m/s

Explanation:

Suppose that at the height of 0 m, the path of the pendulum is lowest.

If we use law of conservation of energy, the pendulum will have zero kinetic energy or K.E when it is at highest point, because K.E happens during movement of object and at the highest point all the energy will be P.E

                                                    P.E= mgh

Similarly, when the pendulum reaches at the lowest point, the height becomes zero and the P.E also becomes zero. Now all the energy will be K.E

                                               K.E= 1/2 m v^2

In question, we are asked about the speed as the pendulum  it reaches the lowest point of its path. Like we mentioned P.E will be zero at lowest point  because of zero height. And also we will use law of conservation of energy because no energy has been lost from system.

                                                  K.E=     P.E

                                       1/2 m v^2  =   mgh

Taking sq.root at both sides

                                                  v= Under root 2 gh

                                                   v=Under root 2x 9.8 m/s x0.4 m

                                                   v=Under root 7.84

                                                    v=2.8 m/sec

Hope it helps!

3 0
3 years ago
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