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Korvikt [17]
3 years ago
12

A skier descends a mountain at an angle of 35.0º to the horizontal. If the mountain is 235 m long, what are the horizontal and v

ertical components of the skier's displacement? (Use trigonometry to solve.) x = y = .
Physics
2 answers:
Masja [62]3 years ago
7 0

Total displacement along the length of mountain is given as

L = 235 m

angle of mountain with horizontal = 35 degree

now we will have horizontal displacement as

x = L cos35

x = 235 cos35 = 192.5 m

similarly for vertical displacement we can say

y = L sin35

y = 235 sin35 = 134.8 m

Sonja [21]3 years ago
5 0

Answer:

x  = 193 m

y = 135 m

Explanation:

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Ira Lisetskai [31]

Answer:

a)  f_{e} = 3,375 cm , b)  f₀ = 77.625 cm

Explanation:

The magnification of a telescope is, to see at the far point of vision (infinity image)

        m = - f₀ /  f_{e}

The length of the tube is

        L = f₀ + f_{e}

a) The focal length of the eyepiece

       L = - m  f_{e} +  f_{e}

       L = f_{e} (1-m)

        f_{e} = L / (1-m)

Let's calculate

        f_{e} = 81.0 / (1 - (-23.0)

        f_{e} = 3,375 cm

b) the focal length of the target

       f₀ = -m  f_{e}

       f₀ = 23 (3.68)

       f₀ = 77.625 cm

8 0
4 years ago
Please help me! As quickly as possible
k0ka [10]

Answer:

1. matter

2. kilograms

3. same

4. gravitational

5. gravity

6. space

7. weightlessness

8. Newton

9. weight

10. more

I HOPE THESE ARE CORRECT AND IT HELPS

7 0
2 years ago
What is the speed of a bobsled whose distance-time graph indicates that it traveled 124m in 26s
krek1111 [17]
It's average speed during that 26 seconds was about 4.77 m/s. Without seeing the graph, we can't tell if it was going faster or slower at any particular time during that period. All we can tell is its average for the full interval.
5 0
4 years ago
At 900.0 K, the equilibrium constant (Kp) for the following reaction is 0.345. 2SO2(g)+O2(g)→2SO3(g) At equilibrium, the partial
elena55 [62]

Answer : The partial pressure of SO_3 is, 67.009 atm

Solution :  Given,

Partial pressure of SO_2 at equilibrium = 30.6 atm

Partial pressure of O_2 at equilibrium = 13.9 atm

Equilibrium constant = K_p=0.345

The given balanced equilibrium reaction is,

2SO_2(g)+O_2(g)\rightleftharpoons 2SO_3(g)

The expression of K_p will be,

K_p=\frac{(p_{SO_3})^2}{(p_{SO_2})^2\times (p_{O_2})}

Now put all the values of partial pressure, we get

0.345=\frac{(p_{SO_3})^2}{(30.6)^2\times (13.9)}

p_{SO_3}=67.009atm

Therefore, the partial pressure of SO_3 is, 67.009 atm

6 0
3 years ago
A nucleus with a mass number of 64 has a mean radius of about: _________.
dangina [55]

Answer:

The correct option is A

Explanation:

From the question we are told that

The mass number is A= 64

Generally the mean radius is mathematically evaluated as

R  =  R_o A^{\frac{1}{3} }

Here R_o is a constant with a value  R_o =1.2*10^{-15}

So  

     R  =  1.2*10^{-15} *  64^{\frac{1}{3} }

      R  =   4.8 *10^{-15}

        R  =   4.8\ fm

5 0
3 years ago
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