The answer is 12.5 mL.
Solution:
<u>M, 6.00M V₁ =?</u>
M2 = 3.00M, V₂ = 25.0mL
<u>M1V1 = M2 V2/M1</u>
V1 = M2V2 M,
V1 = 25.0X3.00/6.00
∴ V1 = 12.5 mL
The initial concentration of the resulting solution is 2 molar which is the volume multiplied by the concentration. The volume of the starting solution is therefore 2,500 ml × 2.25 mol. Calculate the number of moles of HCl dissolved in a given volume of acid by reacting an acid with CaCO3.
This is essentially a double exchange reaction with the decomposition of one of the products. To determine the amount of stock solution required divide the number of moles of glucose by the molarity of the stock solution.
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<span>We're diluting the first solution to make the second solution. This means both solutions will contain the same amount of H2SO4 (it's the concentration of it that changes). If you look at it this way, it's easy to find the unknown mass. Call this unknown mass m.
m * 0.875 = 275 g * 0.55 --> m = 173 g
What I'm saying here is 87.5% of the mass of the first solution needs to be the same as 55% of the mass of the second solution, because you're using the same amount of H2SO4 in both.
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