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alekssr [168]
3 years ago
5

How many grams of a stock solution that is 87.5 percent H2SO4 by mass would be needed to make 275 grams of a 55.0 percent by mas

s solution? Show all of the work needed to solve this problem.
Chemistry
1 answer:
Mandarinka [93]3 years ago
3 0
<span>We're diluting the first solution to make the second solution. This means both solutions will contain the same amount of H2SO4 (it's the concentration of it that changes). If you look at it this way, it's easy to find the unknown mass. Call this unknown mass m. m * 0.875 = 275 g * 0.55 --> m = 173 g What I'm saying here is 87.5% of the mass of the first solution needs to be the same as 55% of the mass of the second solution, because you're using the same amount of H2SO4 in both.

Please mark this brainliest! 


</span>
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Answer:

Explanation:

Lithium, Potassium and Sodium follow each other in that order when it comes to reactivity.

Succinctly put, Lithium is the most reactive. Potassium is more reactive and Sodium is the least reactive.

Also, for Calcium, Strontium and Barium. It is the least reactive in this order.

Strontium, Barium, Calcium

That is, Strontium is more reactive than Barium, which is more reactive than Calcium. Calcium is the least reactive of the 3

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4 years ago
NaCl+F2=NaF+Cl2 balancing chemical equations
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Answer:

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Explanation:

7 0
4 years ago
Ammonia gas has a molar mass of approximately 17 grams per mole. At 290K and 1.2 atm, a sample of ammonia has a volume of 3.7 L.
jeka94

Ammonia gas will have a mass of 3.17grams.

HOW TO CALCULATE MASS:

  • The mass of a substance can be calculated by multiplying the number of moles in the substance by its molar mass.

  • However, to calculate the number of moles present in the ammonia gas given in this question, we use the formula as follows:

  • PV = nRT

where;

  1. P = pressure (atm)
  2. V = volume (L)
  3. n = number of moles (mol)
  4. R = gas law constant
  5. T = temperature

n = PV ÷ RT

n = (1.2 × 3.7) ÷ (0.0821 × 290)

n = 4.44 ÷ 23.81

n = 0.186mol

  • Mass = 0.186 × 17

  • Mass of ammonia gas = 3.17g

  • Therefore, the mass of ammonia gas is 3.17grams.

Learn more at: brainly.com/question/21085277?referrer=searchResults

6 0
3 years ago
What is a single layer of graphite called<br> Asking for GCSE Chemistry
lara31 [8.8K]

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8 0
2 years ago
To what volume should you dilute 60.0 mL of a 4.50 M KI solution so that 30.0 mL of the diluted solution contains 3.25 g of KI?
SpyIntel [72]

Answer:

You should dilute to 414.1 mL

Explanation:

Let's apply the dilution formula to solve this:

M conc . Vol conc = M dil . Vol dil

Molarity for concentrated solution → 4.50 M

Volume for concentrated solution → 60 mL

Molarity for diluted solution → Unknown

Volume for diluted solution → Answer

Let's determine the molarity for diluted solution with data given.

We convert the mass of KI to moles

3.25 g . 1 mol/166 g = 0.0195 moles

Let's convert the volume from mL to L

30 mL . 1 L/1000mL = 0.030 L

Molarity (mol/L) = 0.0195 mol /0.030L = 0.652 M

We replace the data in the formula

4.50 M . 60 mL = 0.652 M . Volume for diluted solution

(4.50M . 60mL) / 0.652M = Volume for diluted solution

414.1 mL = Volume for diluted solution

7 0
3 years ago
Read 2 more answers
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