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alekssr [168]
3 years ago
5

How many grams of a stock solution that is 87.5 percent H2SO4 by mass would be needed to make 275 grams of a 55.0 percent by mas

s solution? Show all of the work needed to solve this problem.
Chemistry
1 answer:
Mandarinka [93]3 years ago
3 0
<span>We're diluting the first solution to make the second solution. This means both solutions will contain the same amount of H2SO4 (it's the concentration of it that changes). If you look at it this way, it's easy to find the unknown mass. Call this unknown mass m. m * 0.875 = 275 g * 0.55 --> m = 173 g What I'm saying here is 87.5% of the mass of the first solution needs to be the same as 55% of the mass of the second solution, because you're using the same amount of H2SO4 in both.

Please mark this brainliest! 


</span>
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Answer and Explanation:

a) The direction is shown in the cube diagram attached to this solution.

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Cos Φ = (h₁h₂ + k₁k₂ + l₁)/√((h₁² + k₁² + l₁²)(h₂² + k₂² + l₂²))

For (111) and (112)

Cos Φ = (1.1 + 1.1 + 1.2)/√((1² + 1² + 1²)(1² + 1² + 2²))

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Cos Φ = 4/√(3×6)

Cos Φ = 4/√18

Φ = cos⁻¹ (4/√18) = 19.56°

c) equation 3.3 is missing from the question, I would be back to provide the answers to that as soon as the equation is provided!

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3 years ago
How would you seprate a mixture of sand and salt?
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4 years ago
The entropy change for a real, irreversible process is equal to:______.
taurus [48]

Answer:

The entropy change for a real, irreversible process is equal to <u>zero.</u>

The correct option is<u> 'c'.</u>

Explanation:

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8 0
3 years ago
Pls help asap!!!!
AVprozaik [17]

Answer: The pressure of the He is 2.97 atm

Explanation:

According to Dalton's law, the total pressure is the sum of individual pressures.

p_{total}=p_{N_2}+p_{O_2}+p_{He}.

Given : p_{total} =total pressure of gases = 6.50 atm

p_{N_2} = partial pressure of Nitrogen = 1.23 atm

p_{O_2} = partial pressure of oxygen = 2.3 atm

p_{He} = partial pressure of Helium = ?

putting in the values we get:

6.50atm=1.23atm+2.3atm+p_{He}  

p_{He}=2.97atm

The pressure of the He is 2.97 atm

3 0
3 years ago
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