Answer:
The answer is D. 0.60 L
Explanation:
The balanced reaction equation including states of matter is;
H₂SO₄(aq) + 2NaOH(aq) → Na₂SO₄(aq) + 2H₂O(l)
More simple:
H2SO4 + 2NaOH → Na2SO4 + 2H2O
Now, we can see from this reaction equation that the mole ratio of NaOH to H2SO4 is 2:1
Number of moles of H2SO4 reacted = 1.2 moles
Hence;
2 moles of NaOH reacts with 1 mole of H2SO4
x moles of NaOH reacts with 1.2 moles of H2SO4
x = 2 * 1.2/1 = 2.4 moles of NaOH
Recall that;
Number of moles = Concentration * Volume
Volume = number of moles/concentration
Volume of NaOH is obtained from;
Volume = 2.4 moles/ 4.0 M
Volume = 0.60 L
It means that the fit and well adjusted ones thrive and "make it", and the weak ones that can't adapt die.
<span>A chemical bond is a lasting attraction between atoms, ions or molecules that enables the formation of chemical compounds. The bond may result from the electrostatic force of attraction between oppositely charged ions as in ionic bonds; or through the sharing of electrons as in covalent bonds. The strength of chemical bonds varies considerably; there are "strong bonds" or "primary bond" such as metallic, covalent or ionic bonds and "weak bonds" or "secondary bond" such as Dipole-dipole interaction, the London dispersion force and hydrogen bonding.</span>
Answer:
I think that the trend that would be seen in the time column of the data table would be that the number of seconds would increase. I know this because for each flask, the concentration of sodium thiosulfate decreases, since less of it is being mixed with more water. Also, when the concentration of a substance decreases, then the reaction rate also decreases, as there will be fewer collisions with sulfuric acid if there are fewer moles of sodium thiosulfate. When there are fewer collisions in a reaction, the reaction itself will take longer, and so when the sodium thiosulfate is diluted, the reaction takes more time.
Explanation:
<em>I verify this is correct. </em>
A combustion reaction of an will generally produce CO2 and H20 -- carbon dioxide and water and/or an oxide
looking at the combustion material C2H2, you know that the end products will be CO2 and H20, so the question is how much of each will you get
well, look at the total amount of carbon atoms, 2 C2, which means a total of 4 carbon atoms in this reaction, since only CO2 has carbon atoms, that means there must be 4 CO2 as an end product and 4 CO2 will use up 4 of 5 O2 molecule leaving only 1 O2 molecule for the H2 reaction.
now O2 has a total of 2 oxygen molecules whereas H20 has only a single oxygen molecule, hence the end product must have 2 H20
check that the H atoms balance out on both sides
