Answer:
The pH for a 0.117 M solution of NaHA is 2.227
Explanation:
To solve the question we check the difference in the Ka values thus
Ka₁ / Ka₂ = 7500000 < 10⁸ so we are required to calculate each value as follows
We therefore have
H₂X→ H⁺¹+HX⁻¹ with Ka₁ = 3.0 × 10⁻⁴
Therefore
3.0 × 10⁻⁴ = (x²)/(0.117)
x² = 3.0 × 10⁻⁴ ×0.117 and x = 5.925 × 10⁻³ = [H⁺]
Similarly
Ka₂ = 4.0 × 10⁻¹¹
and
4.0 × 10⁻¹¹= (x²)/(0.117)
x²= 0.117× 4.0 × 10⁻¹¹
x= 2.16× 10⁻⁶
Total H⁺ = 5.925 × 10⁻³+2.16× 10⁻⁶ = 5.927 × 10⁻³
Since pH = -log of hydrogen ion concentration,
pH = - log 5.927 × 10⁻³ = 2.227
Answer:
if you are working with hazardous materials.
Explanation:
A properly operating and correctly used fume hood can reduce or eliminate exposure to volatile liquids, dusts, and mists. It is advisable to use a laboratory hood when working with all hazardous substances.
<span>Find
the elements sodium, oxygen, and phosphorus on the periodic table. Describe the
monoatomic ions each would form. Then, given what you know about chemical
bonding, describe and give the formulas for the types of ionic compounds they
would produce with each other. </span>
This is so as the liquid you are heating is copper (II) sulfate (I think so) so when you heat it to saturation, there will still be some water molecules left behind, which will allow copper (II) sulfate crystals to be formed since there is water of crystallisation. so the formula is (CuSO4.5H2O).
Hence, if you heat it for a longer period of time when all the water has evaporated, you will obtain a white powder (CuSO4) as crystals cannot form without water of crystallisation
Depending on the type of pea, the peas should come to the top as they are lighter and larger. Then just scoop or brush them off into another container. If you separate it into smaller batches and work them one by one, you should then find you get pure rice batches left which you can put in their own container.
