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RideAnS [48]
3 years ago
15

Jeremy goes to the store where he buys 18 bananas. After two days, he notices that there are only 10 bananas that are left. Whic

h equation below would Jeremy use to find the percent of bananas that he has left?
A. 10/18 = 100/x
B. 18/10 = x/100
C. 5/9 = x/100
D. 10/18 = x/55.5
Mathematics
1 answer:
ss7ja [257]3 years ago
4 0
Total number of Bananas = 18
Number of Bananas that are left = 10

Percentage of Bananas that are left = x

Mathematically, x can be expressed as:

x= \frac{10}{18} * 100 \\  \\ 
 \frac{x}{100}= \frac{10}{18} \\  \\   
 \frac{x}{100}= \frac{5}{9}

Thus the correct percentage of number of bananas that are left is expressed by option c.
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180-48/2

Step-by-step explanation:

180-48=

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One canned juice drink is 25% orange juice; another is 10% orange juice. How many liters of each should be mixed together in ord
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Let's say we use "x" of the 25% OJ... ok... well, how much juice is really in that "x" liters?  well, 25% of it is OJ, the rest is water, how much is 25% of x? well, (25/100) * x,  or 0.25x.

likewise, we'll use "y" of the 10% OJ, and it will end up with (10/100) *y or 0.10y of juice in it.

whatever "x" and "y" are, they must add up to 15 Liters, and the juice concentration on that mixture, must also be the sum of their sum concentration.

\bf \begin{array}{lccclll}
&\stackrel{liters}{amount}&\stackrel{juice~\%}{quantity}&\stackrel{juice}{quantity}\\
&------&------&------\\
\textit{25\% juice}&x&0.25&0.25x\\
\textit{10\% juice}&y&0.10&0.10y\\
------&------&------&------\\
mixture&15&0.17&2.55
\end{array}
\\\\\\
\begin{cases}
x+y=15\implies \boxed{y}=15-x\\
0.25x+0.10y=2.55\\
----------\\
0.25x+0.10\left(\boxed{15-x}  \right)=2.55
\end{cases}
\\\\\\
0.25x-0.10x+1.5=2.55\implies 0.15x=1.05\implies x=\cfrac{1.05}{0.15}
\\\\\\
x=7

how much will be it of the 10% juice?  well, y = 15 - x.
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Bad White [126]

Answer:

1/5

Step-by-step explanation:

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7nadin3 [17]
<h3>Answer: 104 degrees</h3>

================================

Work Shown:

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-------------

Break arc BCD into its smaller pieces

arc BCD = (minor arc BC) + (minor arc CD)

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194-90 = minor arc CD

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<h3>minor arc CD = 104 degrees</h3>
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