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svlad2 [7]
3 years ago
9

An 800-N woman stands on a scale in an elevator. What does the scale read when the elevator is...

Physics
1 answer:
denpristay [2]3 years ago
4 0

Answer:

A) 800 N

B) 865.28 N

C) 734.28 N

Explanation:

Given,

The weight of the woman, W = 800 N

Therefore, the mass of the women is

                                m = W/g

                                    = 800/9.8

                                     = 81.53 Kg

A) If the elevator is ascending with a constant velocity, the external acceleration of the body is zero,

Then the elevator readings are

                                        W = mg + ma

                                           = 800 + 0

                                            = 800 N

The elevator reading of the person ascending at constant velocity W = 800 N

B) Ascending at a constant acceleration of 0.8 m/s²

Then the elevator reading are

                                       W = mg + ma

                                            = 800 + (81.65 x 0.8)

                                            = 865.28 N

The elevator reading ascending at constant acceleration is, W = 865.28 N

C) The elevator reading descending at constant acceleration,

                                       W = 800 + (81.65 x 0.8)

                                            = 734.72 N

Hence, the elevator reading descending at constant acceleration is, W = 734.72 N                                        

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You push your couch a distance of 3.9 m across the living room floor with a horizontal force of 220.0 n. the force of friction i
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The general formula to calculate the work is:

W=Fd \cos \theta

where F is the force, d is the displacement of the couch, and \theta is the angle between the direction of the force and the displacement. Let's apply this formula to the different parts of the problem.


(a) Work done by you: in this case, the force applied is parallel to the displacement of the couch, so \theta=0^{\circ} and \cos \theta=1, therefore the work is just equal to the product between the horizontal force you apply to push the couch and the distance the couch has been moved:

W=Fd=(220.0 N)(3.9 m)=858 J


(b) work done by the frictional force: the frictional force has opposite direction to the displacement, therefore \theta=180^{\circ} and \cos \theta=-1. Therefore, we must include a negative sign when we calculate the work done by the frictional force:

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(c) The work done by gravity is zero. In fact, gravity (which points downwards) is perpendicular to the displacement of the couch (which is horizontal), therefore \theta=90^{\circ} and \cos \theta=0: this means

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(d) Work done by the net force:

The net force is the difference between the horizontal force applied by you and the frictional force:

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Since the rays are parallel P = inf

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