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ahrayia [7]
4 years ago
10

) The centre of a mass, m, is at a distance, r, from the centre of a larger mass M. Assuming there are no other masses present,

what is the maximum gravitational potential energy that mass m and mass M can have in this situation? Your value must be explained to gain any marks.
Physics
1 answer:
ivanzaharov [21]4 years ago
8 0

Answer:

U = - G m M / r

Explanation:

The gravitational potential energy is given by the expression

         U = - G m₁ m₂ / r

dodne G is the gravitational cosntnate (G = 6.67 10⁻¹¹¹), m and m are the mass of the bodies involved

subtype the given values

         U = - G m M / r

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A red rubber ball rolls down a hill from rest with an acceleration of 7.8 m/s 2 . How fast is it moving after it has traveled 5
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In aircraft design, the pressure coefficient Cp is usually measured during wind tunnel testing of an aircraft component to predi
Elza [17]

Answer:

Check the explanation

Explanation:

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 Kindly check the attached image below for the step by step explanation to the question above.

3 0
3 years ago
(1 pt) A bucket of water of mass 20 kg is pulled at constant velocity up to a platform 35 meters above the ground. This takes 14
Elenna [48]

Answer:

w = 5832.372 Joules

Explanation:

Mass of water, m = 20 kg

The water was pulled up to a height of 35 meters, i.e. h = 35 m

It takes 14 minutes to pull up the water through the height, 35 m

speed = distance/ time = 35/14 = 2.5 m/min

The bucket's height, y = speed * time = 2.5t meters

6 kg of water drips out of the bucket throughout the 14 minutes

The rate at which the water drips drips out = (6/14) = 0.4286 kg/min

Mass of water that drips out in time, t = 0.4286t kg

The mass of water remaining = (20 - 0.4286t) kg

Change in Workdone, Δw = mgΔy

Δy = 2.5 Δt

Δw = mg *  2.5 Δt

dw =  (20 - 0.4286t)g2.5 dt

integrating both sides

dw = (50g - 1.07gt)dt

w = \int\limits^a_b {(50g-1.07gt)} \, dx where b = 0, a = 14

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w = 6860 - 1027.628

w = 5832.372 Joules

3 0
4 years ago
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