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Scilla [17]
4 years ago
9

The outer planets _____.all have rings

Physics
2 answers:
serious [3.7K]4 years ago
8 0

Answer:

all have rings

are made of gas

are found outside the astroid belt

Anettt [7]4 years ago
6 0
Are found outside the asteroid belt. Hope it helps!
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Does high pressure rise and low pressure sink
sergeinik [125]
High pressure<span> is associated with sinking air, and </span>low pressure<span> is associated with </span>rising air t<span>he opposite occurs with </span>high pressure<span>. Air is moving away from the </span>high pressure<span> center at the surface so as a result, air from above must </span>sink <span>to take its place.</span>
6 0
3 years ago
Read 2 more answers
If a bus travels for 5 hours at 40mph,how far does it travel
Anastaziya [24]

Answer:

200

Explanation:

5 x 40 = 200

4 0
4 years ago
A feather of mass 0.001 kg falls from a height of 2 m. Under realistic conditions, it experiences air resistance. Based on what
guajiro [1.7K]
Explanation:

Two objects that only have the force of gravity acting on them, will fall with the same acceleration <span>g=9.8<span>m<span>s2</span></span>; g=32.2<span><span>ft</span><span>s2</span></span></span> and will therefore hit the ground at the same time.

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hope this can give u a little bet more to know about how to get ur answer :P 

have a gud day and gud luck!

7 0
3 years ago
A Ferris wheel on a California pier is 27 m high and rotates once every 32 seconds in the counterclockwise direction. When the w
Leto [7]

A) 140 degrees

First of all, we need to find the angular velocity of the Ferris wheel. We know that its period is

T = 32 s

So the angular velocity is

\omega=\frac{2\pi}{T}=\frac{2\pi}{32 s}=0.20 rad/s

Assuming the wheel is moving at constant angular velocity, we can now calculate the angular displacement with respect to the initial position:

\theta= \omega t

and substituting t = 75 seconds, we find

\theta= (0.20 rad/s)(75 s)=15 rad

In degrees, it is

15 rad: x = 2\pi rad : 360^{\circ}\\&#10;x=\frac{(15 rad)(360^{\circ})}{2\pi}=860^{\circ} = 140^{\circ}

So, the new position is 140 degrees from the initial position at the top.

B) 2.7 m/s

The tangential speed, v, of a point at the egde of the wheel is given by

v=\omega r

where we have

\omega=0.20 rad/s

r = d/2 = (27 m)/2=13.5 m is the radius of the wheel

Substituting into the equation, we find

v=(0.20 rad/s)(13.5 m)=2.7 m/s

6 0
3 years ago
The magnitude of the action potential is correlated with the strength of the stimulating input. True or False
Vesnalui [34]

Answer:

True

Explanation:

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