Answer:
The longest possible values of the other two sides are 7 ft and 14 ft
Step-by-step explanation:
Let one side of the triangle be x and the other, 2x
Perimeter of a triangle = sum of all sides; i.e x+2x+33
Therefore, x+2x+12=33
Solve for x;
3x=33-12
3x=21
Divide both sides by 3; x=21/3
therefore, x=7 and
2x= (2*7) = 14
The longest possible values of the other two sides are 7 ft and 14 ft
Answer:
2x^2 -13x-27
Step-by-step explanation:
I hope you get it
Let the number be 'x'
Since, the product of number and 4 less than twice that number is 336.
![x \times [(2 \times x) -4] = 336](https://tex.z-dn.net/?f=x%20%5Ctimes%20%5B%282%20%5Ctimes%20x%29%20-4%5D%20%3D%20336)
![x[2x -4] = 336](https://tex.z-dn.net/?f=x%5B2x%20-4%5D%20%3D%20336)
Now, we will split the middle term, we get
So, 
So, x = 14 or x = -12
Therefore, the negative number is '-12'.
Answer: 15 lines of symmetry.
Step-by-step explanation:
This is a fairly tedious problem. The only way to solve that I see is to simply list out all the possible cases and go through each one by one. You'll use the triangle inequality theorem to see if the triangles can be formed. The theorem says that a+b > c must be true for all sets of pairs. In other words, take any two sides and add them up. The sum must be greater than the third side.
Going through all the combos possible (that I could find), this is what I got
Blue9,Green7,Orange4
Blue9,Green7,Purple12
Blue9,Green7,Red3
Blue9,Green7,Yellow5
Blue9,Orange4,Purple12
Blue9,Purple12,Yellow5
Green7,Orange4,Yellow5
Green7,Red3,Yellow5
Orange4,Red3,Yellow5
In all, I count 9 cases. So the answer to problem 1 is 9.
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For problem 2, the best way may be to pick two segments at a time instead of one. However, I have a feeling that will take just as long as the first method. I haven't tried it out. Even though going through the rods one at a time takes a while, it's probably the best option so you don't overlook any cases.
