For y=x^2-6x-11
complete the square
so roots
set y=0
0=x^2-6x-11
group x terms
0=(x^2-6x)-11
take 1/2 of linear coefient (-6) and square it
-6/2=-3, (-3)^2=9
add positive and neative to inside of parenthasees
0=(x^2-6x+9-9)-11
complete square
0=((x-3)^2-9)-11
expand
0=(x-3)^2-9-11
0=(x-3)^2-20
add 20 to both sides
20=(x-3)^2
sqrt both sides
remember positive and negative roots
+/-2√5=x-3
add 3 to both sides
3+/-2√5=x
so
x=3+2√5 and 3-2√5
Answer:
Probability of an event must be from 0 to 1.
Here,6/5 is more than 1 i.e. 1.2.
Hence,the answer is incorrect.
Answer:
≈ 565.5 units²
Step-by-step explanation:
The area (A) of the shaded sector = area of circle × fraction of circle
A = πr² × 
← r is the radius
= π × 20² ×
= 400π × 0.45 ≈ 565.5 units²
