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frez [133]
4 years ago
12

A ball is thrown from the top of a 50-ft building with an upward velocity of 24 ft/s. When will it reach its maximum height? How

far above the ground will it be?
Mathematics
1 answer:
svp [43]4 years ago
8 0
If you times it the answer is going to be 1,200 
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(5/2,5)

Step-by-step explanation:

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Help for points and Ill give brainliest to correct!
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Ghella [55]

Answer:

It's 4

Step-by-step explanation:

* / = square root

You simply 2/72 which is 12/2, then simplify /8 which is 2/2.

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The equation should be 12/2 over 3/2 so you simplify it which will give you 4.

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3 years ago
An egg that has been falling for x seconds has dropped at an average speed of 16x feet per second. If the egg is dropped from th
ivanzaharov [21]

average \: rate \: of \: fall = 16x \: feet \: per \: second \\ duration \: of \: fall \: (time) =  x \: seconds \\ distance \: of \: fall = 16x \: feet \: per \: second \times x \: seconds \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  =x(16x) \: feet \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   = 16 {x}^{2} \: feet \\  \: the \: egg \: traveled \: 16 {x}^{2} \: feet \: in \: x \: seconds.
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4 years ago
Step by step workout of ;<br> log x^3+log 5x=5 log 2-log 2/5
Charra [1.4K]

Answer:

x = 2

Step-by-step explanation:

log  \: {x}^{3}  + log \: 5x = 5log \: 2 - log \:  \frac{2}{5}  \\  \\  \therefore \: log( {x}^{3}  \times 5x) = log  {2}^{5} - log \:  \frac{2}{5}  \\  \\ \therefore \: log( 5{x}^{4}) = log 32 - log \:  \frac{2}{5} \\  \\ \therefore \: log( 5{x}^{4}) = log  \bigg(32  \times  \frac{5}{2}  \bigg) \\  \\ \therefore \: log( 5{x}^{4}) = log  \bigg(16  \times  5) \\  \\ \therefore \: 5{x}^{4}=  16  \times  5 \\  \\ \therefore \: {x}^{4}=   {2}^{4}   \\  \\  \huge \purple{ \boxed{\therefore \: {x} = 2}}

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