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dimaraw [331]
3 years ago
14

A glass of juice at 20°C was kept in the open. After 30 minutes, the temperature of the Juice remained the same. Which statement

is correct?
A) The temperature of the surrounding air was greater than 20°C

B) The temperature of the surrounding air was less than 20°C

C) The temperature of the juice was equal to the temperature the surrounding air

D) The temperature the juice was less than the final temperature of the surrounding air
Physics
2 answers:
devlian [24]3 years ago
7 0

The answer would be B the temperature of the juice was the temperature of the surrounding air

just olya [345]3 years ago
6 0

Answer: The temperature of the juice was equal to the temperature of the surrounding air.

Explanation:

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jonny [76]

Explanation:

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A cube of mass m1=9.6 kgm1=9.6 kg is sitting on top of a second cube of the same size and mass m2=0.8 kgm2=0.8 kg while both are
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kykrilka [37]

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Then, divide 20.93 m/s by 5.0s

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Brums [2.3K]

The car’s velocity at the end of this distance is <em>18.17 m/s.</em>

Given the following data:

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To find the car’s velocity at the end of this distance, we would use the third equation of motion;

Mathematically, the third equation of motion is calculated by using the formula;

V^2 = U^2 + 2dS

Substituting the values into the formula, we have;

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<em>Final velocity, V = 18.17 m/s</em>

Therefore, the car’s velocity at the end of this distance is <em>18.17 m/s.</em>

<em></em>

Read more: brainly.com/question/8898885

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Answer: I don't understand

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