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Setler [38]
3 years ago
5

What does telescope mean?

Physics
1 answer:
Leviafan [203]3 years ago
5 0

Answer:

Something used to see objects that's really far from you.

Explanation:

mostly used to see objects that are outer space.

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Gravity pushes objects away from each other TRUE OR FALSE
e-lub [12.9K]

Answer:

false

Explanation:

5 0
3 years ago
How much current must be applied across a 60 Ω light bulb filament in order for it to consume 55 W of power? Unserious answers w
sergij07 [2.7K]

Answer: current I = 0.96 Ampere

Explanation:

Given that the

Resistance R = 60 Ω 

Power = 55 W

Power is the product of current and voltage. That is

P = IV ...... (1)

But voltage V = IR. From ohms law.

Substitutes V in equation (1) power is now

P = I^2R

Substitute the above parameters into the formula to get current I

55 = 60 × I^2

Make I^2 the subject of formula

I^2 = 55/60

I^2 = 0.92

I = sqr(0.92)

I = 0.957 A

Therefore, 0.96 A current must be applied.

4 0
3 years ago
When an object is in a gravitational field, it has energy in its __________ __________ energy store.what’s is the word in the mi
lisabon 2012 [21]

Answer:

I don't know if this is right or not but I think its Potential Energy

Explanation:

8 0
3 years ago
A block with mass m is pulled horizontally with a force F_pull leading to an acceleration a along a rough, flat surface.
Simora [160]

Answer:

\mu_k=\frac{a}{g}

Explanation:

The force of kinetic friction on the block is defined as:

F_k=\mu_kN

Where \mu_k is the coefficient of kinetic friction between the block and the surface and N is the normal force, which is always perpendicular to the surface that the object contacts. So, according to the free body diagram of the block, we have:

N=mg\\F_k=F=ma

Replacing this in the first equation and solving for \mu_k:

ma=\mu_k(mg)\\\mu_k=\frac{a}{g}

6 0
3 years ago
A pen contains a spring with a spring constant of 270 N/m. When the tip of the pen is in its retracted position, the spring is c
vodka [1.7K]

Answer:

-0.9045 j

Explanation:

Here K= 270 N/m

distance 1 = 4.60 mm=0.0046 m

when pen is compressed ;

distance 2 = 6.70 mm + distance1 = 0.0067 m+0.0046 m= 0.0113 m

The pen store in itself two types of PE

Which is Initial PEi = 1/2 ×K× [distance 1^{2} =0.5×270×0.0046 =0.621 j

and Final PEf = 1/2 × K × distance 2^{2} = 0.5×270×0.0113=1.5255 j

When the pen gets ready - it goes ahead distance d2 and is then pressed back distance d1 for writing.

Total PE when ready  = 0.621-1.5255= - 0.9045 j

so, work =  -0.9045 j

8 0
3 years ago
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