1. The subscript when writing the notation is always dedicated to the atomic number of the element. Since the atomic number for Mercury, Hg, is 80, then the subscript is <em>80</em>.
2. For the second problem, you just have to balance out the subscripts and superscripts of the reactions.
Superscripts: 203 = 203 + ?; To balance, the missing number would be 0.
Subscripts: 80 = 81 + ?; To balance, the missing number would be -1.
<em>Hence the particle produced is actually an <u>electron</u>, or a <u>beta particle</u> (not an element). The <u>mass number is 0</u>, and the <u>atomic number is 0 </u>(since it does not contain any proton).</em>
There's 18 atoms in ammonium phosphate
The original material has decayed 75%
<h3>Further explanation</h3>
Given
two half-life
Required
The decayed sample
Solution
General formulas used in decay:

t = duration of decay
t 1/2 = half-life
N₀ = the number of initial radioactive atoms
Nt = the number of radioactive atoms left after decaying during T time
t = 2 x t 1/2
Input the value :
The amount of Nt = 25% No
Holonium and Gadolinium has the highest number of neutrons in the nucleus.
Looking at the atoms listed;
Dysprosium has 66 protons
Holonium has 67 protons
Neodymium has 60 protons
Europium has 63 protons
Gadolinium has 64 protons
Then,
Number of neutrons = Mass number - number of protons
For Dysprosium
157 - 66 = 91 neutrons
For Holonium
162 - 67 = 95 neutrons
For Neodymium
149 - 60 = 89 neutrons
For Europium
148 - 63 = 85 neutrons
For Gadolinium
159 - 64 = 95 neutrons
Hence, Holonium and Gadolinium has the highest number of neutrons in the nucleus.
Learn more: brainly.com/question/14156701