Answer:
![1.k + 85](https://tex.z-dn.net/?f=1.k%20%2B%2085)
![2.t - 6](https://tex.z-dn.net/?f=2.t%20-%206)
![3. \frac{99 - 19}{6} or \frac{19 - 99}{6}](https://tex.z-dn.net/?f=3.%20%5Cfrac%7B99%20-%2019%7D%7B6%7D%20or%20%5Cfrac%7B19%20-%2099%7D%7B6%7D%20)
i am very sure of the first and second but I have two of the options for the third.
I hope this helps!
Answer:
No
Step-by-step explanation:
No real number when multiplied with zero makes one.
Answer:
the answer is BBBB
Step-by-step explanation:
IT IS BBBB... i think
Answer:
The answer is D) f(x) = 1/3 x^2 <u>-</u><u>1</u>
Step-by-step explanation:
the key is at the end, the minus 1
Answer:
,
![(6, \frac{11\pi}{6} )](https://tex.z-dn.net/?f=%286%2C%20%5Cfrac%7B11%5Cpi%7D%7B6%7D%20%29)
Step-by-step explanation:
Note I'm using a, instead of theta to represent angles.
To convert rectangular to polar, apply these formulas
![r = \sqrt{ {x}^{2} + {y}^{2} }](https://tex.z-dn.net/?f=r%20%3D%20%20%5Csqrt%7B%20%7Bx%7D%5E%7B2%7D%20%2B%20%20%7By%7D%5E%7B2%7D%20%20%7D%20)
![\alpha = \tan {}^{ - 1} ( \frac{y}{x} )](https://tex.z-dn.net/?f=%20%5Calpha%20%20%3D%20%20%5Ctan%20%7B%7D%5E%7B%20-%201%7D%20%28%20%5Cfrac%7By%7D%7Bx%7D%20%29%20)
Note : Rectangular coordinates are the coordinates you were learning since elementary school or middle school.
The first number is x, and the second is y.
So
![r = \sqrt{(3 \sqrt{3} ) {}^{2} + ( - 3) {}^{2} }](https://tex.z-dn.net/?f=r%20%3D%20%20%5Csqrt%7B%283%20%5Csqrt%7B3%7D%20%29%20%7B%7D%5E%7B2%7D%20%2B%20%28%20-%203%29%20%7B%7D%5E%7B2%7D%20%20%7D%20)
![r = \sqrt{36}](https://tex.z-dn.net/?f=r%20%3D%20%20%5Csqrt%7B36%7D%20)
![r = 6](https://tex.z-dn.net/?f=r%20%3D%206)
![\alpha = \tan {}^{ - 1} ( \frac{ - 3}{3 \sqrt{3} } )](https://tex.z-dn.net/?f=%20%5Calpha%20%20%3D%20%20%5Ctan%20%7B%7D%5E%7B%20-%201%7D%20%28%20%5Cfrac%7B%20-%203%7D%7B3%20%5Csqrt%7B3%7D%20%7D%20%29%20)
Since our y coordinate is negative and x coordinate is Positve , on the unit circle, the angle must be in the fourth quadrant.
So the angle must be in between
![\frac{3\pi}{2} < \alpha < 2\pi](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%5Cpi%7D%7B2%7D%20%20%3C%20%20%5Calpha%20%20%3C%202%5Cpi)
![\alpha = \tan {}^{ - 1} ( \frac{ - 1}{ \sqrt{3} } )](https://tex.z-dn.net/?f=%20%5Calpha%20%20%3D%20%20%5Ctan%20%7B%7D%5E%7B%20-%201%7D%20%28%20%5Cfrac%7B%20-%201%7D%7B%20%5Csqrt%7B3%7D%20%7D%20%29%20)
![\alpha = \frac{11\pi}{16}](https://tex.z-dn.net/?f=%20%5Calpha%20%20%3D%20%20%5Cfrac%7B11%5Cpi%7D%7B16%7D%20)
So our answer is
(6, 11pi/6).