Name the 8 levels of classification from the most general most definite

Where is paramcium normally found?

Scilla [17]

Paramecium<span> can be found in aquatic environments, usually in stagnant, warm water.</span>

8 0

3 years ago

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A machine does 500 j of work in 20 sec. What is the power of this machine?

NNADVOKAT [17]

Explanation:

P=W/t

P=500/20

P=25 W

6 0

3 years ago

What step of the rock cycle happens as the sea stacks are broken down

fiasKO [112]

But rocks are not unchangeable! Just like the water cycle, rocks undergo changes of form in a rock cycle. A metamorphic rock can become an igneous rock, or a sedimentary rock can become a metamorphic one. Unlike the water cycle, you can’t see the process happening on a day-to-day basis. Rocks change very slowly under normal conditions, but sometimes catastrophic events like a volcanic eruption or a flood can speed up the process. So what are the three types of rocks, and how do they change into each other? Keep reading to find out!

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3 years ago

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9.

Ghella [55]

Given parameters:

Mass of the body = 200g

Force on the body = 10N

Unknown parameters:

Acceleration produced by the force = ?

To solve this problem we must first define force in terms of mass and acceleration. This is possible due to the Newton's first law of motion.

Force = mass x acceleration

Here the unknown is acceleration and we can easily solve for it.

But we must take the mass to kilogram in order for it to cancel out.

1000g = 1 kg

200g = x kg = $\frac{200}{1000}$ = 0.2kg

Now input the parameters and solve;

10 = 0.2 x acceleration

Acceleration = $\frac{10}{0.2}$ = 50m/s²

The acceleration produced by the body is 50m/s²

4 0

3 years ago

Consider a sound wave moving through the air modeled with the equation s(x, t) = 5.00 nm cos(60.00 m−1x − 18.00 ✕ 103 s−1t). Wha

GaryK [48]

Answer:

Shortest time = 58.18 × 10^(-6) s

Explanation:

We are given;

s(x,t) = 5.00 nm cos((60.00 m^(−1)x) − (18.00 X 10³ s^(−1)t))

Let us set x = 0 as origin.

Now, for us to find the time difference, we need to solve 2 equations which are;

s(x,t) = 5.00 nm cos((60.00 m^(−1)x) − (18.00 X 10³ s^(−1)t1))

And

s(x,t) = 5.00 nm cos((60.00 m^(−1)x) − (18.00 X 10³ s^(−1)t2))

Now, since the wave starts from maxima at time at t = 0, the required time would be the difference (t2 - t1)

Thus, the solutions are;

t1 = (1/(18 × 10³)) cos^(-1) (2.5/5)

And

t2 = (1/(18 × 10³)) cos^(-1) (-2.5/5)

Angle of the cos function is in radians, thus;

t1 = 58.18 × 10^(-6) s

t2 = 116.36 × 10^(-6) s

So,

Required time = t2 - t1 = (116.36 × 10^(-6) s) - (58.18 × 10^(-6) s) = 58.18 × 10^(-6) s

4 0

3 years ago