Name the 8 levels of classification from the most general most definite

Helium–neon laser light (λ = 632.8 nm) is sent through a 0.350-mm-wide single slit. What is the width of the central maximum on

Cloud [144]

Answer:

The width of the central bright fringe is 7.24 mm.

Explanation:

Given that,

Wavelength = 632.8 nm

Width d= 0.350 mm

Distance between screen and slit D= 2.00 m

We need to calculate the distance

Using formula of distance

$y_{m}=\dfrac{\lambda D}{d}$

Put the value into the formula

$y_{m}=\dfrac{632.8\times10^{-9}\times2.00}{0.350\times10^{-3}}$

$y_{m}=3.62\ mm$

We need to calculate the width of the central bright fringe

Using formula of width

$width = 2\times|y_{m}|$

Put the value into the formula

$width=2\times3.62$

$width = 7.24\ mm$

Hence, The width of the central bright fringe is 7.24 mm.

5 0

3 years ago

Two balls undergo a perfectly elastic head-on collision, with one ball initially at rest. if the incoming ball has a speed of 20

melamori03 [73]

what is the final speed of the incoming ball if it is much more massive than the stationary ball? express your answer using two significant figures. v1 = 200 m / s submitprevious answers correct
Perfectly elastic collisions means that both mechanical energy and
momentum are conserved.
Therefore, for this case, we have the equation to find the final velocity of the incoming ball is given by
v1f = ((m1-m2) / (m1 + m2)) v1i
where,
v1i: initial speed of ball 1.
v1f: final speed of ball 1.
m1: mass of the ball 1
m2: mass of the ball 2
Since the mass of the ball 1 is much larger than the mass of the ball 2 m1 >> m2, then rewriting the equation:
v1f = ((m1) / (m1) v1i
v1f = v1i
v1f = 200 m / s
answer
200 m / s
part b part complete what is the final direction of the incoming ball with respect to the initial direction if it is much more massive than the stationary ball? forward submitprevious answers correct

Using the equation of part a, we can include in it the directions:
v1fx = ((m1-m2) / (m1 + m2)) v1ix
v1i: initial velocity of ball 1 in the direction of the x-axis
v1f: final speed of ball 1 in the direction of the x-axis
like m1 >> m2 then
v1fx = v1ix
v1fx = 200 m / s (positive x direction)
So it is concluded that the ball 1 continues forward.
answer:
forward

part c part complete what is the final speed of the stationary ball if the incoming ball is much more massive than the stationary ball ?.
The shock is perfectly elastic. For this case, we have that the equation to find the final velocity of the stationary ball is given by
v2f = ((2m1) / (m1 + m2)) v1i
where,
v1i: initial speed of ball 1.
v2f: final speed of ball 2.
m1: mass of the ball 1
m2: mass of the ball 2
Then, as we know that m1 >> m2 then
v2f = ((2m1) / (m1) v1i
v2f = 2 * v1i
v2f = 2 * (200 m / s)
v2f = 400 m / s
answer
400m / s

7 0

2 years ago

Read 2 more answers

The place kicker on a football team kicks a ball from ground level with an initial speed of 5.80 m/s at an angle of 17.0° above

Likurg_2 [28]

Answer:

0.34 s

Explanation:

Given that,

Initial speed of a ball, u = 5.8 m/s

It is kicked at an angle of 17.0° above the horizontal.

The vertical component of velocity will be,

$u_y=u\sin\theta\\\\=5.8\times \sin 17\\\\=1.69\ m/s$

Let it takes t time in the air before it lands on the ground again. It can calculated as :

$t=\dfrac{2u_y}{g}\\\\t=\dfrac{2\times 1.69}{9.8}\\\\t=0.34\ s$

So, it will take 0.34 seconds.

8 0

2 years ago

As the distance from equilibrium decreases, in what way is the magnitude of the force on an object that is undergoing simple har

nydimaria [60]

The correct answer is B. The force decreases.

Simple harmonic motion is a to and fro motion about the equilibrium position, with the restoring force proportional to the displacement and it is always directed towards the mean position.

Mathematically, the force F is given by,

$F= -kx$

Here, x is the displacement from the equilibrium position and k is the force constant. The negative sign indicates that the direction of the force is always directed towards the equilibrium position, opposite to the direction of the displacement from the equilibrium position.

Thus, as the displacement from the equilibrium position decreases, the force acting on the body also decreases.

4 0

3 years ago

2. Who was the first person to"measure gravity?" (Hint: By "measuring gravity, we mean

babunello [35]

Answer:

The first person to "measure gravity" is sir Issac newton

4 0

3 years ago