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postnew [5]
4 years ago
5

Two long barges are floating in the same direction in still water, one with a speed of 10 km/h and the other with a speed of 20

km/h. While they are passing each other, coal is shoveled from the slower to the faster one at a rate of 1200 kg/min; see Fig. 7-35. How much additional force must be provided by the driving engines of each barge if neither is to change speed? Assume that the shoveling is always perfectly sideways and that the frictional forces between the barges and the water do not depend on the weight of the barges.
Physics
1 answer:
dem82 [27]4 years ago
3 0

Answer:

the answer is 132 kg I think

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a)   I = 0.01029 A , b)   Q = 4074.05 J

Explanation:

a) Let's work in parts, let's start by looking for the energy consumed.

For this we use a rule of three or direct proportions if 1 kWh costs $ 0.09, how much kWh is $ 8.80

           Energy = 8.80 / 0.09

           Energy = 97,778 kWh

to calculate the current, we must have the energy consumed per second

           

Let's use a rule of three if 97,778 kWh were consumed in 24 h = 86,400 s how much was consumed in 1 s

            E₀ = 97.778 1/86400

            E₀ = 1.13168 Ws

           

the power consumed is

           P = E₀ / t

           P = 1.13168 / 1

           P = 1.13168 W

power is

           P = I V

           I = P / V

           I = 1.13168 / 110

           I = 0.01029 A

b) the heat is given by

     

           

as the efficiency is 100%

          E = P t = Q

          Q = 1.131368 3600

          Q = 4074.05 J

6 0
4 years ago
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