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Lostsunrise [7]
4 years ago
8

A book is sliding along a desk top. Because the book is in motion ,you know that the forces acting on the book are A. Balanced B

. Unbalanced C. In One Direction only D. Pushing upward and downward only
Physics
1 answer:
Virty [35]4 years ago
4 0
Just because the book is moving doesn't tell you anything about the forces on it, or even whether there ARE any.

Just look at Newton's first law of motion, and this time, let's try and THINK about it too. It says something to the effect that any object continues in constant, uniform MOTION ..... UNLESS acted on by an external force.
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A ball hits a wall. What is true about the magnitude of the force experienced by the ball compared with the force experienced by
Natalka [10]

Answer:

The ball and the wall experience the same force.

Explanation:

According to the third law of Newton, which states that "for every action, there is an equal and opposite reaction", this means that when an object 1 acts on object 2 with a certain force, object 2 also acts on object 1 with the same magnitude of force but in an opposite direction.

According to this question, a ball hits a wall with a certain force. This means that the wall will react on the ball with the same force magnitude, but in an opposite manner. Hence, the ball and the wall experience the same force.

6 0
3 years ago
HELPPP PLEASE !!!!!!!
vlabodo [156]

Explanation:

a) d = ½.a.t²

200 = ½(4)t²

200 = 2t²

t² = 200/2

t² = 100

t =√100 = 10 s

b) Vt = a. t

= 4(10)

= 40 m/s

c) V av. = d/t = 200/10 = 20m/s

6 0
3 years ago
A 0.300 kg ball, moving with a speed of 2.5 m/s, has a head-on collision with at 0.600 kg ball initially at rest. Assuming a per
FrozenT [24]

Answer:

1.25 m/s

Explanation:

Given,

Mass of first ball=0.3 kg

Its speed before collision=2.5 m/s

Its speed after collision=2 m/s

Mass of second ball=0.6 kg

Momentum of 1st ball=mass of the ball*velocity

=0.3kg*2.5m/s

=0.75 kg m/s

Momentum of 2nd ball=mass of the ball*velocity

=0.6 kg*velocity of 2nd ball

Since the first ball undergoes head on collision with the second ball,

momentum of first ball=momentum of second ball

0.75 kg m/s=0.6 kg*velocity of 2nd ball

Velocity of 2nd ball=0.75 kg m/s ÷ 0.6 kg

=1.25 m/s

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3 years ago
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IrinaVladis [17]

Answer:

Once used as a energy source they cannot be charged/used again.

Explanation:

7 0
3 years ago
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makkiz [27]

Please be determined and being hardworking person do not rely on the other people to make your problems solved

Explanation:

Ok?

5 0
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