Answer:
0.091 sec
Explanation:
f = frequency of oscillation of the mass attached to the spring = 11 Hz
T = Time period of oscillation of the mass attached to the spring = ?
Time period and frequency of oscillation of the mass attached to the end of spring are related as
![T = \frac{1}{f}](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B1%7D%7Bf%7D)
Inserting the values
![T = \frac{1}{11}](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B1%7D%7B11%7D)
T = 0.091 sec
<span>FACTS:
|
|
It’s
that time of year again when the days are wet and cool.
The rainy
season is the best season.
Rain makes up part of Earth’s water cycle.
Water evaporates from streams, lakes, and oceans, then condensation
and
precipitation occur in the form of rain.
Precipitation in the form of
rain is better than snow.
Snow this time of year makes people gloomy.
Rain is a great boon to local farmers.
It helps their crops grow.
</span>OPINIONS:
|
<span>| It’s
that time of year again when the days are wet and cool.
The rainy
season is the best season.
Rain makes up part of Earth’s water cycle.
Water evaporates from streams, lakes, and oceans, then condensation
and
precipitation occur in the form of rain.
Precipitation in the form of
rain is better than snow.
Snow this time of year makes people gloomy.
Rain is a great boon to local farmers.
It helps their crops grow.</span>
Answer:
![[F]=[MLT^{-2}]](https://tex.z-dn.net/?f=%5BF%5D%3D%5BMLT%5E%7B-2%7D%5D)
Explanation:
Newton’s second law states that the acceleration a of an object is proportional to the force F acting on it is inversely proportional to its mass m. The mathematical expression for the second law of motion is given by :
F = m × a
F is the applied force
m is the mass of the object
a is the acceleration due to gravity
We need to find the dimensions of force. The dimension of force m and a are as follows :
![[m]=[M]](https://tex.z-dn.net/?f=%5Bm%5D%3D%5BM%5D)
![[a]=[LT^{-2}]](https://tex.z-dn.net/?f=%5Ba%5D%3D%5BLT%5E%7B-2%7D%5D)
So, the dimension of force F is,
. Hence, this is the required solution.
Answer:
![\alpha = 5.2 \times 10^{-5} per ^oC](https://tex.z-dn.net/?f=%5Calpha%20%3D%205.2%20%5Ctimes%2010%5E%7B-5%7D%20per%20%5EoC)
Explanation:
At room temperature the thickness of the film is just enough that it will cancel the reflected light
So here we will have
![2\mu t = \frac{\lambda}{2}](https://tex.z-dn.net/?f=2%5Cmu%20t%20%3D%20%5Cfrac%7B%5Clambda%7D%7B2%7D)
so we have
![t = \frac{\lambda}{4/mu}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B%5Clambda%7D%7B4%2Fmu%7D)
here we have
![\lambda = 582.3 nm](https://tex.z-dn.net/?f=%5Clambda%20%3D%20582.3%20nm)
![\mu = 1.750](https://tex.z-dn.net/?f=%5Cmu%20%3D%201.750)
now we have
![t = \frac{582.3 nm}{4(1.750)}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B582.3%20nm%7D%7B4%281.750%29%7D)
![t = 83.2 nm](https://tex.z-dn.net/?f=t%20%3D%2083.2%20nm)
now when temperature is increased to 177 degree C
then in this case we have
![\lambda_2 = 587.2 nm](https://tex.z-dn.net/?f=%5Clambda_2%20%3D%20587.2%20nm)
now we have
![t' = \frac{587.2 nm}{4(1.750)}](https://tex.z-dn.net/?f=t%27%20%3D%20%5Cfrac%7B587.2%20nm%7D%7B4%281.750%29%7D)
![t' = 83.89 nm](https://tex.z-dn.net/?f=t%27%20%3D%2083.89%20nm)
now we know by the formula of thermal expansion
![t' = t (1 + \alpha \Delta T)](https://tex.z-dn.net/?f=t%27%20%3D%20t%20%281%20%2B%20%5Calpha%20%5CDelta%20T%29)
![83.89 = 83.2(1 + \alpha(177 - 18.6))](https://tex.z-dn.net/?f=83.89%20%3D%2083.2%281%20%2B%20%5Calpha%28177%20-%2018.6%29%29)
![\alpha = 5.2 \times 10^{-5} per ^oC](https://tex.z-dn.net/?f=%5Calpha%20%3D%205.2%20%5Ctimes%2010%5E%7B-5%7D%20per%20%5EoC)
Answer:
A. It must be zero
Explanation:
A spacecraft leaves the solar system at a velocity of 1,500 m/s. The net force on this spacecraft is zero. What can we say about the spacecraft's acceleration?
According to Newton's second law
Force = Mass × acceleration
If the net force is zero
0 = mass × acceleration
0 = ma
a = 0/m
a = 0m/s²
this shows that the acceleration will be zero If the net force is zero