The distance travelled is 10 m
The velocity gained at the end of the time is 2 m/s
<h3>Motion</h3>
From the question, we are to determine distance travelled and the velocity gained
From one of the equations of motion for <u>linear motion</u>, we have that
S = ut + 1/2at²
Where S is the distance
u is the initial velocity
t is the time taken
and a is the acceleration
First, we will calculate the acceleration
Using the formula,
F = ma
Where F is the force
m is the mass
and a is the acceleration
∴ a = F/m
Where F is the force
and a is the acceleration
From the given information,
F = 50 N
m = 250 kg
Putting the parameters into the equation,
a = 50/250
a = 0.2 m/s²
Thus,
From the information,
u = 0 m/s (Since the object was initially at rest)
t = 10 s
S = 0(t) + 1/2(0.2)(10)²
S = 10 m
Hence, the distance travelled is 10 m
For the velocity
Using the formula,
v = u + at
Where v is the velocity
v = 0 + 0.2×10
v = 2 m/s
Hence, the velocity gained at the end of the time is 2 m/s
Learn more on Motion here: brainly.com/question/10962624
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Answer:
x = 4, -6
Step-by-step explanation:
x = 4, -6
Y=mx+b
Slope is m
Y intercept is b
So it's-4
Step-by-step explanation:
-2+3-12-2
1+15=16 Answer
hope it helps
9514 1404 393
Answer:
7.0
Step-by-step explanation:
The relationship of interest is ...
Tan = Opposite/Adjacent
tan(25°) = x/15
x = 15·tan(25°) ≈ 6.9946
x ≈ 7.0
