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2 years ago

A 15 kg object and a 18 kg object are connected by a massless compressed spring and

Physics

1 answer:

MatroZZZ [7]2 years ago

5 0

Hi there!

This is an example of a recoil collision.

Using the conservation of momentum:

$p_i = p_f$

The initial momentum is 0 kgm/s (objects start from rest), so:

$p_f = 0$

We are given that the 15 kg block has a velocity of 12 m/s to the left, so:

$m_1v_1' + m_2v_2' = 0 \\\\15(-12) + 18v_2' = 0 \\\\$

Solve for v2':

$18v_2' = 180 \\\\v_2' = \boxed{10 m/s}$

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3 years ago

Two ice skaters stand in the middle of an ice rink. Drew has a mass of 75 kg, and Lily has a mass of 55 kg. Drew holds Lily, and

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PART a)

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3 years ago

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3 years ago

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3 years ago

Two balls undergo a perfectly elastic head-on collision, with one ball initially at rest. if the incoming ball has a speed of 20

melamori03 [73]

what is the final speed of the incoming ball if it is much more massive than the stationary ball? express your answer using two significant figures. v1 = 200 m / s submitprevious answers correct
Perfectly elastic collisions means that both mechanical energy and
momentum are conserved.
Therefore, for this case, we have the equation to find the final velocity of the incoming ball is given by
v1f = ((m1-m2) / (m1 + m2)) v1i
where,
v1i: initial speed of ball 1.
v1f: final speed of ball 1.
m1: mass of the ball 1
m2: mass of the ball 2
Since the mass of the ball 1 is much larger than the mass of the ball 2 m1 >> m2, then rewriting the equation:
v1f = ((m1) / (m1) v1i
v1f = v1i
v1f = 200 m / s
answer
200 m / s
part b part complete what is the final direction of the incoming ball with respect to the initial direction if it is much more massive than the stationary ball? forward submitprevious answers correct

Using the equation of part a, we can include in it the directions:
v1fx = ((m1-m2) / (m1 + m2)) v1ix
v1i: initial velocity of ball 1 in the direction of the x-axis
v1f: final speed of ball 1 in the direction of the x-axis
like m1 >> m2 then
v1fx = v1ix
v1fx = 200 m / s (positive x direction)
So it is concluded that the ball 1 continues forward.
answer:
forward

part c part complete what is the final speed of the stationary ball if the incoming ball is much more massive than the stationary ball ?.
The shock is perfectly elastic. For this case, we have that the equation to find the final velocity of the stationary ball is given by
v2f = ((2m1) / (m1 + m2)) v1i
where,
v1i: initial speed of ball 1.
v2f: final speed of ball 2.
m1: mass of the ball 1
m2: mass of the ball 2
Then, as we know that m1 >> m2 then
v2f = ((2m1) / (m1) v1i
v2f = 2 * v1i
v2f = 2 * (200 m / s)
v2f = 400 m / s
answer
400m / s

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3 years ago

Read 2 more answers