What is used to make a cast of a tool mark ?

Determine the magnitude of the force between two 42 m-long parallel wires separated by 0.03 m, both carrying 6.3 A in the same d

xz_007 [3.2K]

Answer:

The magnitude of the force between the two parallel wires is 0.0111 N.

Explanation:

Given;

length of the two parallel wires, L = 42 m

distance between the two wires, r = 0.03 m

current in both wires, I₁, I₂ = 6.3 A

Therefore, the magnitude of the repulsive force between the two parallel wires is given by;

$F = \frac{\mu_0 I_1I_2l}{2\pi r}\\\\where;\\\mu_0 \ is \ permeability \ of \ free \ space = 4\pi *10^{-7} \ T.m/A \\\\F = \frac{(4\pi *10^{-7})(6.3)^2(42)}{2\pi (0.03)}\\\\F = 0.0111 \ N$

Therefore, the magnitude of the force between the two parallel wires is 0.0111 N.

6 0

3 years ago

A force of 25N acts on an object. The work done by the force is 400J. How far dose the object move in the direction of the force

bezimeni [28]

Answer:
C
Explanation:
d=w/f
d=400/25
d= 16

8 0

3 years ago

A stone is thrown straight up from the ground with an initial speed of 44 m/s.At the same instant, a stone is dropped from a hei

Lubov Fominskaja [6]

Answer:

394.26 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.8 m/s²

$v=u+at\\\Rightarrow 0=44-9.8\times t\\\Rightarrow \frac{-44}{-9.8}=t\\\Rightarrow t=4.49 \s$

$s=ut+\frac{1}{2}at^2\\\Rightarrow s=44\times 4.49+\frac{1}{2}\times -9.8\times 4.49^2\\\Rightarrow s=98.77\ m$

$s=ut+\frac{1}{2}at^2\\\Rightarrow 98.77=0t+\frac{1}{2}\times 9.8\times t^2\\\Rightarrow t=\sqrt{\frac{98.77\times 2}{9.8}}\\\Rightarrow t=4.49\ s$

Total time taken by the stone to reach the ground is 4.49+4.49 = 8.97 seconds

$s=ut+\frac{1}{2}at^2\\\Rightarrow h=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{h\times 2}{9.8}}$

The times are equal so,

$8.97=\sqrt{\frac{h\times 2}{9.8}}\\\Rightarrow h=\frac{8.97^2\times 9.8}{2}\\\Rightarrow h=394.26\ m$

The height is 394.26 m

6 0

3 years ago

Part APart complete Make a chart showing all the possible sets of quantum numbers l and ml for the states of the electron in the

Olin [163]

Answer:

Its c

Explanation: I double checked and got it right on brainly.

8 0

3 years ago

A rod of 2.0-m length and a square (2.0 mm x 2.0 mm) cross section is made of a material with a resistivity of 6.0 x 10^-8 0.Ω.m

Ksju [112]

Answer:

Heat generated in the rod is 8.33 watts.

Explanation:

It is given that,

Length of rod, l = 2 m

Area of cross section, $A=2\ mm\times 2\ mm=4\ mm^2=4\times 10^{-6}\ m^2$

Resistivity of rod, $\rho=6\times 10^{-8}\ \Omega-m$

Potential difference, V = 0.5 V

The value of resistance is given by :

$R=\rho\dfrac{l}{A}$

$R=6\times 10^{-8}\ \Omega-m\times \dfrac{2\ m}{4\times 10^{-6}\ m^2}$

R = 0.03 ohms

Let H is the rate at which heat is generated in the rod . It is given by :

$\dfrac{H}{t}=I^2R$

Since, $I=\dfrac{V}{R}$

$\dfrac{H}{t}=\dfrac{V^2}{R}$

$\dfrac{H}{t}=\dfrac{(0.5)^2}{0.03}$

$\dfrac{H}{t}=8.33\ watts$

So, the at which heat is generated in the rod is 8.33 watts. Hence, this is the required solution.

8 0

4 years ago