Answer:
The rise from A to B is 0.887
Solution:
As per the question:
The following reading of an inverted staff is given as:
A = 2.915
B = -2.028
Here, for inverted staff, the greater reading shows greater elevation and lesser reading shows lower elevation.
Thus
The rise from A to B is given as:
A - B = 2.915 - 2.028 = 0.887
1) The electrostatic force between the two pieces of paper is 
2)
- If the charges of the two pieces of paper are both + or both -, they repel each other
- If the charges of one piece of paper is positive and the other one is negative, they attract each other
Explanation:
1)
The electrostatic force between two charged objects is given by Coulomb's law:

where:
is the Coulomb's constant
are the two charges
r is the separation between the two charges
In this problem, we have the following situation:
is the charge on the first piece of paper
is the charge on the second piece of paper
is their separation
Substituting into the equation, we find the magnitude of the electrostatic force between them:

2)
The electrostatic force can be either attractive of repulsive, depending on the relative sign of the charges of the objects involved.
In particular, we have:
- If the two charges have same sign (both positive or both negative), the force between them is repulsive
- If the two charges have opposite sign (one positive and one negative), the force between them is attractive
Therefore, in this case:
- If the charges of the two pieces of paper are both + or both -, they repel each other
- If the charges of one piece of paper is positive and the other one is negative, they attract each other
Learn more about electric force:
brainly.com/question/8960054
brainly.com/question/4273177
#LearnwithBrainly
Answer:
frequency is 195.467 Hz
Explanation:
given data
length L = 4.36 m
mass m = 222 g = 0.222 kg
tension T = 60 N
amplitude A = 6.43 mm = 6.43 ×
m
power P = 54 W
to find out
frequency f
solution
first we find here density of string that is
density ( μ )= m/L ................1
μ = 0.222 / 4.36
density μ is 0.050 kg/m
and speed of travelling wave
speed v = √(T/μ) ...............2
speed v = √(60/0.050)
speed v = 34.64 m/s
and we find wavelength by power that is
power = μ×A²×ω²×v / 2 ....................3
here ω is wavelength put value
54 = ( 0.050 ×(6.43 ×
)²×ω²× 34.64 ) / 2
0.050 ×(6.43 ×
)²×ω²× 34.64 = 108
ω² = 108 / 7.160 ×
ω = 1228.16 rad/s
so frequency will be
frequency = ω / 2π
frequency = 1228.16 / 2π
frequency is 195.467 Hz
It’s not arrested because if you look closer it’s plug walk I don’t even understand how it talk tho
For numbers 1 and 3 it is giving you the answers i believe
number 1 would be 20 joules of potential energy on the far left and far right point
number 3 would the (3rd) point as it says it has 20 joules of kinetic energy
sorry if this doesn’t help