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Talja [164]
3 years ago
12

Mass of sodium + nitrogen +oxygen+ oxygen+ oxygen =

Chemistry
2 answers:
Mazyrski [523]3 years ago
8 0

<u>Answer:</u>

<em>Mass of sodium + nitrogen +oxygen+ oxygen+ oxygen = =85 g/mol </em>

<em></em>

<u>Explanation:</u>

Molar mass is the mass of 1 mole of the substance and its unit is g/mol

We find the molar mass by just adding atomic mass of the elements present in the chemical formula of the compound

For example  

H_2 SO_4

Atomic mass of H is 1.008 (approximately 1)

Atomic mass of S is 32

Atomic mass of O is 16

There are 2, H atoms 1, S atom and 4, O atoms

So, the molar mass of the compound H_2 SO_4 will be

\\$=[(2 \times 1)+(1 \times 32)+(4 \times 16)]$\\\\$=(2+32+64)=98 \frac{g}{m o l}$

The question says 1, Na  

1, N and  

3, O

So the chemical formula we get is NaNO_3

The molar mass of the compound NaNO_3 is

\\$=[(1 \times 23)+(1 \times 14)+(3 \times 16)]$\\\\$=(23+14+48)$

=85 g/mol (Answer)

Vaselesa [24]3 years ago
5 0

Answer:

Oxygen's atomic weight is 16.00 amu. 1 mole of oxygen is 6.02 x 1023 atoms of oxygen 1 amu = 1.661 x 10-24g What is the molar mass (g/mole) of oxygen? Molar mass (in grams) is always equal to the atomic weight of the atom!

Explanation:

i looked it up ok

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How many grams of aluminum are required to react with 35 mL of 2.0 M hydrochloric acid, HCl?__ HCl + __ Al --&gt; __ AlCl3 + __
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Answer:

0.6258 g

Explanation:

To determine the number grams of aluminum in the above reaction;

  • determine the number of moles of HCl
  • determine the mole ratio,
  • use the mole ratio to calculate the number of moles of aluminum.
  • use RFM of Aluminum to determine the grams required.

<u>Moles </u><u>of </u><u>HCl</u>

35 mL of 2.0 M HCl

2 moles of HCl is contained in 1000 mL

x moles of HCl is contained in 35 mL

x \: mol \:  =  \:  \frac{2 \:  \times  \: 35}{1000}  \\  = 0.07 \: moles \:

We have 0.07 moles of HCl.

<u>Mole </u><u>ratio</u>

  • Balanced equation

6HCl(aq) + 2Al(s) --> 2AlCl3(aq) + 3H2(g)

Hence mole ratio = 6 : 2 (HCl : Al

  • but moles of HCl is 0.07, therefore the moles of Al;

=  \frac{2}{6}  \times 0.07 \\  \:  = 0.0233333 \: moles

Therefore we have 0.0233333 moles of aluminum.

<u>Grams of </u><u>Aluminum</u>

We use the formula;

grams \:  = moles \:  \times  \: rfm

The RFM (Relative formula mass) of aluminum is 26.982g/mol.

Substitute values into the formula;

= 0.0233333 \: moles  \:  \times  \: 26.982 \:  \frac{g}{mol}  \\  = 0.625799 \: grams

The number of grams of aluminum required to react with HCl is 0.6258 g.

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