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Talja [164]
3 years ago
12

Mass of sodium + nitrogen +oxygen+ oxygen+ oxygen =

Chemistry
2 answers:
Mazyrski [523]3 years ago
8 0

<u>Answer:</u>

<em>Mass of sodium + nitrogen +oxygen+ oxygen+ oxygen = =85 g/mol </em>

<em></em>

<u>Explanation:</u>

Molar mass is the mass of 1 mole of the substance and its unit is g/mol

We find the molar mass by just adding atomic mass of the elements present in the chemical formula of the compound

For example  

H_2 SO_4

Atomic mass of H is 1.008 (approximately 1)

Atomic mass of S is 32

Atomic mass of O is 16

There are 2, H atoms 1, S atom and 4, O atoms

So, the molar mass of the compound H_2 SO_4 will be

\\$=[(2 \times 1)+(1 \times 32)+(4 \times 16)]$\\\\$=(2+32+64)=98 \frac{g}{m o l}$

The question says 1, Na  

1, N and  

3, O

So the chemical formula we get is NaNO_3

The molar mass of the compound NaNO_3 is

\\$=[(1 \times 23)+(1 \times 14)+(3 \times 16)]$\\\\$=(23+14+48)$

=85 g/mol (Answer)

Vaselesa [24]3 years ago
5 0

Answer:

Oxygen's atomic weight is 16.00 amu. 1 mole of oxygen is 6.02 x 1023 atoms of oxygen 1 amu = 1.661 x 10-24g What is the molar mass (g/mole) of oxygen? Molar mass (in grams) is always equal to the atomic weight of the atom!

Explanation:

i looked it up ok

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What is the unknown metal if the temperature of a beaker of 100ml of water was raised 17c to 19 c when 21 grams of the metal at
horrorfan [7]

Answer:

The metal has a heat capacity of 0.385 J/g°C

This metal is copper.

Explanation:

<u>Step 1</u>: Data given

Mass of the metal = 21 grams

Volume of water = 100 mL

 ⇒ mass of water = density * volume = 1g/mL * 100 mL = 100 grams

Initial temperature of metal = 122.5 °C

Initial temperature of water = 17°C

Final temperature of water and the metal = 19 °C

Heat capacity of water = 4.184 J/g°C

<u />

<u>Step 2: </u>Calculate the specific heat capacity

Heat lost by the metal = heat won by water

Qmetal = -Qwater

Q = m*c*ΔT

m(metal) * c(metal) * ΔT(metal) = - m(water) * c(water) * ΔT(water)

21 grams * c(metal) *(19-122.5) = -100 * 4.184 * (19-17)

-2173.5 *c(metal) = -836.8

c(metal) = 0.385 J/g°C

The metal has a heat capacity of 0.385 J/g°C

This metal is copper.

4 0
4 years ago
How many protons neutrons and electrons does nitrogen 14 have?
vazorg [7]
Many nitrogen atoms have seven neutrons<span> (14-7 = 7). Some atoms of nitrogen, however, have eight electrons. They are atoms of N-15, an isotope of nitrogen. In a neutral atom, the number of protons must equal the number of electrons.</span>
5 0
3 years ago
Sodium bicarbonate is the chemical name for baking soda.Its chemical formula is NaHCO3.What does the subscript 3 mean?
prisoha [69]

Answer:

3 moles of Oxygen

Explanation:

The chemical formula of a compound is a representation which shows all the elements therein and the mole relationship between them expressed as subscripts.

   NaHCO₃  implies:

      1 mole of baking soda contains:

     1 mole of Na

     1 mole of Hydrogen

     1 mole of carbon

  And 3 moles of Oxygen

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The Michaelis constant for pancreatic lipase is 5 mM. At 60 C, lipase is subject to deactivation with a half-life of 8 min. Fat
Dmitriy789 [7]

Explanation:

According to the given data, we will calculate the following.

 Half life of lipase t_{1/2} = 8 min x 60 s/min

                                       = 480 s

Rate constant for first order reaction is as follows.

         k_{d} = \frac{0.6932}{480}

                        = 1.44 \times 10^{-3}s^{-1}&#10;

Initial fat concentration S_{o} = 45 mol/m^{3}

                                                = 45 mmol/L

Rate of hydrolysis V_m_{o} = 0.07 mmol/L/s

Conversion X = 0.80

Final concentration (S) = S_{o} (1 - X)

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                                      = 9 mol/m^{3}

or,                                  = 9 mmol/L

It is given that K_{m} = 5mmol/L

Therefore, time taken will be calculated as follows.

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Now, putting the given values into the above formula as follows.

            t = -\frac{1}{K_{d}}ln[1 - \frac{K_{d}}{V}{K_{M} ln (\frac{S_{o}}{S}) + (S_{o} - S)]  

             = -\frac{1}{1.44 \times 10^{-3}s^{-1}}ln[1 - \frac{1.44 \times 10^{-3}s^{-1}}{0.07 mmol/L/s&#10;}{K_{M} ln (\frac{45 mmol/L&#10;}{9 mmol/L&#10;}) + (45 mmol/L - 9 mmol/L&#10;)]

              = 1642.83 s \times \frac{1 min}{60 sec}

              = 27.38 min

Therefore, we can conclude that time taken by the enzyme to hydrolyse 80% of the fat present is 27.38 min.

6 0
3 years ago
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