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Talja [164]
3 years ago
12

Mass of sodium + nitrogen +oxygen+ oxygen+ oxygen =

Chemistry
2 answers:
Mazyrski [523]3 years ago
8 0

<u>Answer:</u>

<em>Mass of sodium + nitrogen +oxygen+ oxygen+ oxygen = =85 g/mol </em>

<em></em>

<u>Explanation:</u>

Molar mass is the mass of 1 mole of the substance and its unit is g/mol

We find the molar mass by just adding atomic mass of the elements present in the chemical formula of the compound

For example  

H_2 SO_4

Atomic mass of H is 1.008 (approximately 1)

Atomic mass of S is 32

Atomic mass of O is 16

There are 2, H atoms 1, S atom and 4, O atoms

So, the molar mass of the compound H_2 SO_4 will be

\\$=[(2 \times 1)+(1 \times 32)+(4 \times 16)]$\\\\$=(2+32+64)=98 \frac{g}{m o l}$

The question says 1, Na  

1, N and  

3, O

So the chemical formula we get is NaNO_3

The molar mass of the compound NaNO_3 is

\\$=[(1 \times 23)+(1 \times 14)+(3 \times 16)]$\\\\$=(23+14+48)$

=85 g/mol (Answer)

Vaselesa [24]3 years ago
5 0

Answer:

Oxygen's atomic weight is 16.00 amu. 1 mole of oxygen is 6.02 x 1023 atoms of oxygen 1 amu = 1.661 x 10-24g What is the molar mass (g/mole) of oxygen? Molar mass (in grams) is always equal to the atomic weight of the atom!

Explanation:

i looked it up ok

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3 years ago
If 3.5 grams of NaN3 decomposed, how many grams of N2 would be produced?
Wewaii [24]

Answer:

5.25 moles.

Explanation:

The decomposition reaction of NaN₃ is as follows :

2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)

We need to find how many grams of N₂ produced in the process.

From the above balanced chemical reaction, we conclude that the ratio of moles of sodium azide and nitrogen gas are 2 : 3.

2 moles of sodium azide decomposes to give 3 moles of nitrogen gas. So,

3.5 moles of sodium azide decomposes to give \dfrac{3}{2}\times 3.5=5.25 moles of nitrogen gas.

Hence, the number of moles produced is 5.25 moles.

6 0
2 years ago
What is the partial pressure of carbon dioxide in a container that contains 3.63 mol of oxygen, 1.49 mol of nitrogen, and 4.49 m
lana66690 [7]

Answer:

Partial pressure of CO₂ is 406.9 mmHg

Explanation:

To solve the question we should apply the concept of the mole fraction.

Mole fraction = Moles of gas / Total moles

We have the total moles of the mixture, if we have the moles for each gas inside. (3.63 moles of O₂, 1.49 moles of N₂ and 4.49 moles of CO₂)

Total moles = 3.63 mol O₂ + 1.49 mol N₂ + 4.49 mol CO₂ = 9.61 moles

To determiine the partial pressure of CO₂ we apply

Mole fraction of CO₂ → mol of CO₂ / Total moles = P. pressure CO₂ / Total P

Partial pressure of CO₂ = (mol of CO₂ / Total moles) . Total pressure

We replace values: (4.49 moles / 9.61 moles) . 871 mmHg = 406.9 mmHg

6 0
3 years ago
Read 2 more answers
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