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3 years ago

What weather types affect earthworms?

Chemistry

1 answer:

torisob [31]3 years ago

4 0

Usually when it rains the worms surface!

HOPE THIS HELPS!

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Which generates waves that are capable of traveling through a vacuum?

CaHeK987 [17]

Answer:

Light bulbs

Explanation:

light waves are electromagnetic waves which can travel through a vacuum

7 0

3 years ago

Suppose of barium acetate is dissolved in of a aqueous solution of ammonium sulfate. Calculate the final molarity of barium cati

ollegr [7]

Explanation:

Let us assume that the given data is as follows.

mass of barium acetate = 2.19 g

volume = 150 ml = 0.150 L (as 1 L = 1000 ml)

concentration of the aqueous solution = 0.10 M

Therefore, the reaction equation will be as follows.

$Ba(C_{2}H_{3}O_{2})_{2} \rightarrow Ba^{2+} + 2C_{2}H_{3}O^{-}_{2}$

Hence, moles of $C_{2}H_{3}O^{-}_{2}$ = $2 \times Ba(C_{2}H_{3}O_{2})_{2}$ .......... (1)

As, No. of moles = $\frac{mass}{\text{molar mass}}$

Hence, moles of $Ba(C_{2}H_{3}O_{2})_{2}$ will be calculated as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{2.19 g}{255.415 g/mol}$ (molar mass of $Ba(C_{2}H_{3}O_{2})_{2}$ is 255.415 g/mol)

= $8.57 \times 10^{-3}$

Moles of $C_{2}H_{3}O^{-}_{2}$ = $2 \times 8.57 \times 10^{-3}$

= 0.01715 mol

Hence, final molarity will be as follows.

Molarity = $\frac{\text{no. of moles}}{volume}$

= $\frac{0.01715 mol}{0.150 L}$

= 0.114 M

Thus, we can conclude that final molarity of barium cation in the solution is 0.114 M.

5 0

3 years ago

A solid is held in shape by strong forces.

n200080 [17]

Ok thanks for the valuble info.

8 0

3 years ago

Read 2 more answers

What is the mass in g of 7.009 x 10^21 molecules of Pl3?

ycow [4]

I have completed the problem

4 0

3 years ago

Select the correct statement (2.5 points) (A) Elements in the same row are similar in size. (B) Elements in the same column have

Mrrafil [7]

Answer:

Explanation:

We are talking about the periodic table in which elements where put under different rows and columns according to their atomic number (number of protons) in ascendant order.

In rows or periods we can find trends in some properties like atomic radius, electronegativity, etc...). So they are not similar in size. Option A is a false statement.

Also, they were organized in groups or columns according to their similar electronic configuration and chemical properties (like noble gases, halogens, etc...) This means option B is the correct statement.

8 0

3 years ago

Read 2 more answers