Question

Need Help ASAP

Answer 1

a. pH=2.07

b. pH=3

c. pH=8

Further explanation

pH=-log [H⁺]

a) 0.1 M HF Ka = 7.2 x 10⁻⁴

HF= weak acid

$\tt [H^+]=\sqrt{Ka.M}\\\\(H^+]=\sqrt{7.2.10^{-4}\times 0.1}\\\\(H^+]=8.5\times 10^{-3}\\\\pH=3-log~8.5=2.07$

b) 1 x 10⁻³ M HNO₃

HNO₃ = strong acid

$\tt pH=-log[1\times 10^{-3}]=3$

c) 1 x 10⁻⁸ M HCl

$\tt pH=-log[1\times 10^{-8}]=8$