a. We can calculate the amount of work by calculating the area under the graph.
first area (rectangular): 2.5 x 6 = 15
second area(trapezoid): 1/2 x (6+10) x 2.5 =20
total work done: 35 J
b. the force was first applied = 6 N
F = m.a
a = 6 : 3 = 2 m/s²
vf²=vi²+2as
vf²=6²+2.2.5
vf²=56
vf=7.5 m/s
Answer: Tension = 53.6N
Explanation:
Given that
Height h = 1 m
Time t = 1.7 s.
Mass m = 5.1 kg
From the equation of the motion we can get the acceleration of the elevator:
h = X0+ V0t + at2/2;
Th elevator starts from rest with a constant upward acceleration. Initial velocity Vo = 0, also Xo = 0; thus
a = 2h/t2 = 2 × 1/1.7^2
a = 0.69 m/s2.
Then we can find the tension in the cord by using the formula
T = mg + ma
= 5.1 (9.8 + 0.69)
= 5.1 × 10.5
= 53.6N
Answer:
35.2 ps
Explanation:
Hello!
A US short ton is equal to 2 000 pounds, therefore:
2.25 tons = 4500 pounds
Now lets convert the area of each tire footprint:
1 cm = 0.393701 in
12.5 cm = 4.92126 in
16.5 cm = 6.49607 in
Therefore, the area of the footprint is: 31.9688 in^2
Then, the pressure exerted by the car is given by the weigth devided by the total area, that is 4 times the area of the footprint :
4500 /(4 * 31.9688) psi = 35.1906 psi
Rounding to the first tenth
35.2 psi
