Answer:
Pushing molecules like a wave.
Explanation:
Answer:
sorry but which class your talking 'bout
Explanation:
The magnetic force acting on a current carrying wire in a uniform magnetic field is given by :
or
Where
is the angle between length and the magnetic field
The magnetic force is perpendicular to both current and magnetic field. It is maximum when it is perpendicular to both current and magnetic field.
So, the correct options are :
- The magnetic force on the current-carrying wire is strongest when the current is perpendicular to the magnetic field lines.
- .The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the field.
- The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the current.
<span>Using the kinematic equations below, we can calculate the initial velocity required.
Angle of projectile = 60 degrees
Acceleration due to gravity (Ay) = -10 m/s^2 (negative because downward)
Height of projectile (Dy) = 2m
Vfy^2=Voy^2 +2*Ay*Dy
Vfy = 0 m/s because the vertical velocity slows to zero at the height of its trajection.
So... 0 = Voy^2 + 2(-10)(2)
0 = Voy^2 - 40
40 = Voy^2
Sqrt40 = Voy
6.32 m/s = Voy
THIS IS NOT THE ANSWER. THIS IS JUST THE INITIAL VELOCITY IN THE Y DIRECTION.
Using trigonometry, Tan 60 = Voy/Vox. Tan 60 = 6.32/Vox. Vox*Tan 60 = Vox
Vox = 10.95 m/s. Now, using Vox = 10.95 and Voy = 6.32, we can use pythagorean theorem to find the total Vo. A^2 +B^2 = C^2
10.95^2 + 6.32^2 = C^2
Solving for C = 12.64 m/s
This is the velocity required to hit the surface. You can also calculate a bunch of other stuff now using the other kinematic equations.
V = 12.64 m/s</span>
