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3 years ago

6

Auroras occur in the what atmosphere

1 answer:

kotegsom [21]3 years ago

8 0

The answer is thermasphere

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What can electricty from solar power be used for

Mandarinka [93]

Regular electrical needs such as heat, a/c, appliances, anything that would be used regularly with electricity. Most electrical companies use gas, coal, and other nonrenewable resources to power houses. Solar power is just a renewable way of gathering power from the sun and converting it to electricity.

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2 years ago

I GIVE CROWNS!!<br> I need how you worked it out as well please because I don't know how to do it.

RoseWind [281]

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2 years ago

katrin2010 [14]

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2 years ago

A car travels due east 14 miles in 18 minutes. Then, the car turns around and returns to its starting point, taking an additiona

N76 [4]

Answer:

(a) The average speed is 0.85 milles/minute

(b) The average velocity is zero

Explanation:

In order to answer part (a) and (b) you have to apply the formulas for average speed and average velocity which are:

<em>-Average speed formula:</em>

$v=\frac{d}{t}$

where d is the total distance traveled and t is the tota time

Replacing the given values:

$v=\frac{14+14}{18+15}\\v=\frac{28}{33} \\v=0.85$ milles/minute

Notice that you have to replace the total distance, which is 14 milles for the go plus 14 milles for the return. The same for the total time.

<em>-Average velocity formula:</em>

V = Δx/Δt

Where V is the velocity vector, Δx is the displacement and Δt is the change in time

V= $\frac{X2-X1}{t2-t1}$

Where X2 is the final position and X1 is the initial position

In this case X1= 0 i and X2=0 i (i is the unit vector in the x direction). So, the displacement is zero.

Therefore, the average velocity is:

V= 0 i [milles/minute]

4 0

3 years ago

A circular wire loop has a radius of 7.50 cm. a sinusoidal electromagnetic plane wave traveling in air passes throughthe loop, w

ExtremeBDS [4]

Intensity of electromagnetic wave is given as

$I = 2[\frac{B_{rms}^2}{2\mu_0}\times c]$

given that

$I = 0.0275 W/m^2$

$0.0275 = \frac{B_{rms}^2}{\mu_0} \times c$

here we know that

$\mu_0 = 4\pi \times 10^{-7}$

$c = 3 \times 10^8 m/s$

now we have

$0.0275 = \frac{B_{rms}^2}{4 \pi \times 10^{-7}}(3 \times 10^8)$

$B_{rms} = 1.07 \times 10^{-8} T$

now we will have

$B_0 = \sqrt2 B_{rms}$

$B_0 = 1.52 \times 10^{-8} T$

frequency of wave is given as

$f = \frac{c}{\lambda}$

$f = \frac{3 \times 10^8}{6.90} = 4.35 \times 10^7 Hz$

now the induced EMF is given as

$EMF = B_0A2\pi f$

$EMF = 1.52 \times 10^{-8} \times \pi(0.075)^2 \times (2\pi \times 4.25 \times 10^7)$

$EMF = 0.0733 Volts$

7 0

3 years ago

Read 2 more answers