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Masja [62]
3 years ago
14

Usain Bolt ran the 100m dash in 9.69 seconds. How fast does he run in the 100m dash?​

Physics
1 answer:
Alla [95]3 years ago
3 0
The answer is in the question, it’s 9.69
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Throw two balls from the same height at the same time at an initial speed of 20 m/s. One is thrown vertically down, while the ot
labwork [276]

The time difference between their landing is 2.04 seconds.

<h3>Time of difference of the two balls</h3>

The ball thrown vertical upwards will take double of the time taken by the ball thrown vertically downwards.

Time difference, = 2t - t = t

t = √(2h/g)

where;

  • h is the height of fall
  • g is acceleration due to gravity

Apply the principle of conservation of energy;

¹/₂mv² = mgh

h = v²/2g

where;

  • v is speed of the ball

h = (20²)/(2 x 9.8)

h = 20.41 m

<h3>Time of motion</h3>

t = √(2 x 20.41 / 9.8)

t = 2.04 s

Thus, the time difference between their landing is 2.04 seconds.

Learn more about time of motion here: brainly.com/question/2364404

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2 years ago
The player who is serving continues to serve until he/she or their team commits a fault.
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Answer:

true

Explanation:

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3 years ago
If an element has 2 valence electrons, how many dots will be in the elements dot diagram?
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Well since we're doing the Lewis dot diagram do you know which element on the table that it is? 
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A water pipe is inclined 40.0° below the horizontal. The radius of the pipe at the upper end is 2.00 cm. If the gauge pressure a
aliya0001 [1]

Answer:

P_2 = -1.9 \times 10^8 Pa

Explanation:

As it is given that flow rate in the pipe is 20 cm^3/s

so we have

Q = A_1v_1 = A_2v_2

at the upper end the area is given as

A_1 = \pi r_1^2

A_1 = \pi(0.02)^2 = 1.26 \times 10^{-3} cm^2

Also at the other end

A_2 = \pi r_2^2

A_2 = \pi(0.01)^2 = 0.314 \times 10^{-3} cm^2

now the speed at two ends is given as

v_1 = \frac{20}{1.26 \times 10^{-3}}

v_1 = 159.15 m/s

v_2 = \frac{20}{0.314 \times 10^{-3}}

v_2 = 637 m/s

now by Bernoulli's theorem we have

P_1 + \frac{1}{2}\rho v_1^2 + \rho g h_1 = P_2 + \frac{1}{2}\rho v_2^2 + \rho g h_2

now we have

0.112(1.013 \times 10^5) + \frac{1}{2}1000(159.15)^2 + 1000(9.81)(2.65sin40) = P_2 + \frac{1}{2}(1000)(637)^2 + 0

Now we have

P_2 = -1.9 \times 10^8 Pa

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Consider a point on a bicycle wheel as the wheel makes exactly four complete revolutions
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It makes a cycloid pattern in parametrics if that's what you're asking~
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