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IRISSAK [1]
3 years ago
14

The following balanced equation shows the formation of water.

Chemistry
2 answers:
ss7ja [257]3 years ago
8 0
Mole ratio of H₂  :  O₂   is   2  :  1

∴ if mole of H₂  =  1.67 mol

then mole of O₂ =  \frac{1.67   mol}{2}

⇒ that mole of oxygen needed to react with H₂  =  0.835 mol

The answer is A
saveliy_v [14]3 years ago
8 0

Answer: A) 0.835 mol of O_2

Explanation: According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

As can be seen from the given balanced equation:

2H_2+O_2\rightarrow 2H_2O

2 moles of hydrogen are required to react completely with 1 mole of oxygen.

Thus 1.67 moles of hydrogen will react with=\frac{1}{2}\times 1.67=0.835 moles of oxygen.

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Why does electronegativity increase as you move through a period on the periodic table?
velikii [3]

Answer:the size of the atom increases is your answer have a great day

Explanation:

5 0
3 years ago
Need help with balancing equations
solniwko [45]

The balanced equation of the reaction shows that the mole of atoms on both sides of the reaction are equal.

<h3>What are balanced chemical equations?</h3>

Balanced chemical equations are equations in wgich the moles of each species on both sides of the reaction are equal.

To balance chemical equations, numerical coefficients are placed in front of the species in the reaction.

The balanced equations of the reaction are as follows:

3Pd + 4H_3PO_4 \rightarrow Pd_3(PO_4)_4 + 6H_2 \\

C_{11}H_{24} + 17O_2 \rightarrow 11CO_2 + 12H_2O \\

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Therefore, the balanced equation of the reaction shows that the mole of atoms on both sides of the reaction are equal.

Learn more about balancing equations at: brainly.com/question/11904811

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7 0
3 years ago
You need to produce a buffer solution that has a pH of 5.26. You already have a solution that contains 10. mmol (millimoles) of
Andreas93 [3]

The question is incomplete, complete question is :

You need to produce a buffer solution that has a pH of 5.50. You already have a solution that contains 10 mmol (millimoles) of acetic acid. How many millimoles of acetate (the conjugate base of acetic acid) will you need to add to this solution? The pka of acetic acid is 4.74.

Answer:

33.11 millimoles of acetate we will need to add to this solution.

Explanation:

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

pH=pK_a+\log(\frac{[salt]}{[acid]})

Where :

tex]pK_a[/tex] = negative logarithm of acid dissociation constant of acid

[salt] = Concentration of salt

[Acid] = Concentration of salt

We have:

pH = 5.26

pK_a=4.74

[salt] =[CH_3COO^-] = ?

[acid] = [CH_3COOH]=10.0 mmol

5.26=4.74+\log(\frac{[CH_3COO^-]}{[10.0 mmol]})

[CH_3COO^-]=33.11 mmol

33.11 millimoles of acetate we will need to add to this solution.

3 0
4 years ago
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