The following balanced equation shows the formation of water.
2 answers:
Mole ratio of H₂ : O₂ is 2 : 1
∴ if mole of H₂ = 1.67 mol
then mole of O₂ =
⇒ that mole of oxygen needed to react with H₂ = 0.835 mol
The answer is A
∴ if mole of H₂ = 1.67 mol
then mole of O₂ =
⇒ that mole of oxygen needed to react with H₂ = 0.835 mol
The answer is A
Answer: A) 0.835 mol of
Explanation: According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.
As can be seen from the given balanced equation:
2 moles of hydrogen are required to react completely with 1 mole of oxygen.
Thus 1.67 moles of hydrogen will react with= moles of oxygen.
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Answer:
a. Polar
b. Polar
c. Non-polar
d. Non-polar
Explanation:
a. , hydronium cation contains a positive charge. Just as any other ion, it is polar, as it has a net charge.
b. has the same shape as water. There are two lone pairs on sulfur atom which produce an overall dipole moment in this molecule, the bent structure is polar.
c. is non-polar, as the central atom, phosphorus, doesn't contain any lone pairs, all the dipole moments cancel out: two dipole moments in the vertical plane, P-Cl, and three P-Cl dipoles in the horizontal plane within a trigonal bipyramidal shape.
d. is non-polar, since it's a tetrahedral molecule with no lone pairs on carbon atom, all four C-F dipole moments cancel out to yield a net 0 dipole moment.
Answer:
Q = 0.50
No
Left
Explanation:
At a generic reversible equation
aA + bB ⇄ cC + dD
The reaction coefficient (Q) is the ratio of the substances concentrations:
Solids and liquid water are not considered in this calculus.
When the reaction achieves equilibrium (concentrations are constant), the Q value is named as Kc, which is the equilibrium constant of the reaction. If Q > Kc, it indicates that the concentration of the products is higher, so, the reaction must progress to the left and form more reactants; if Q < Kc, than the concentrations of the reactants, are higher, so, the reaction progress to the right.
In this case:
Q =
Q = 0.50
So, Q > Kc, the reaction is not at equilibrium and it progresses to the left.