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3 years ago

The following balanced equation shows the formation of water.

2 answers:

8 0

Mole ratio of H₂ : O₂ is 2 : 1

∴ if mole of H₂ = 1.67 mol

then mole of O₂ = $\frac{1.67 mol}{2}$

⇒ that mole of oxygen needed to react with H₂ = 0.835 mol

The answer is A

saveliy_v [14]3 years ago

8 0

Answer: A) 0.835 mol of $O_2$

Explanation: According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

As can be seen from the given balanced equation:

$2H_2+O_2\rightarrow 2H_2O$

2 moles of hydrogen are required to react completely with 1 mole of oxygen.

Thus 1.67 moles of hydrogen will react with= $\frac{1}{2}\times 1.67=0.835$ moles of oxygen.

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The image represents a typical temperate forest food web. Use the image to answer the following questions(s).

Nikolay [14]

Answer:

Answer is D

Explanation:

secondary consumers eat meat and manly eat the primary consumers

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2 years ago

Read 2 more answers

A sample of baking soda, naHCO3, always contains 27.37% by mass of sodium, 1.20% of hydrogen, 14.30% of carbon, and 57.14% of ox

Dvinal [7]

Answer: Law of definite proportion.

Explanation: Law of definite proportion states that any chemical compound consists of elements in a fixed ratio by their masses. This law is also known as Proust's Law.

We are given a chemical compound $NaHCO_3$

Assuming that the total mass of 1 mole of $NaHCO_3$ = 100 grams

where

Mass of Sodium = 27.37 grams

Mass of Hydrogen = 1.20 grams

Mass of Carbon = 14.30 grams

Mass of Oxygen = 57.14 grams

To Calculate the ratio of all the elements, we divide each of the masses by the lowest mass.

$\text{Mass ratio of Sodium}=\frac{27.37}{1.20}=22.80\approx 23$

$\text{Mass ratio of Hydrogen}=\frac{1.20}{1.20}=1$

$\text{Mass ratio of Carbon}=\frac{14.30}{1.20}=11.91\approx 12$

$\text{Mass ratio of Oxygen}=\frac{57.14}{1.20}=47.61\approx 48$

Mass ratio of elements in $NaHCO_3=Sodium:Hydrogen:Carbon:Oxygen$

Na : H : C : O = 23 : 1 : 12 : 48

For every $NaHCO_3$ compound, this mass ratio will always be constant.

4 0

3 years ago

Describe the number of signals and their splitting in the 1H NMR spectrum of (CH3)2CHOCH3.

yanalaym [24]

Answer:

d. 3 signals: a singlet, a doublet, and a septet

Explanation:

In this case, we can start with the structure of $(CH_3)_2CHOCH_3$ . When we draw the molecule we will obtain 2-methoxypropane (see figure 1).

In 2-methoxypropane we will have three signals. The signal for the $CH_3$ groups in the left, the $CH$ and the $CH_3$ in the right. Lets analyse each one:

-) $CH_3$ in the right

In this carbon, we dont have any hydrogen as neighbors. Therfore we will have singlet signal in this carbon.

-) $CH$

In this case, we have 6 hydrogen neighbors ( the two methyl groups in the left). So, if we follow the n + 1 rule (where n is the amount of hydrogen neighbors):

$multiplicity~=~n+1~=~6~+~1~=~7$