Answer:
![H = 10.05 m](https://tex.z-dn.net/?f=H%20%3D%2010.05%20m)
Explanation:
If the stone will reach the top position of flag pole at t = 0.5 s and t = 4.1 s
so here the total time of the motion above the top point of pole is given as
![\Delta t = 4.1 - 0.5 = 3.6 s](https://tex.z-dn.net/?f=%5CDelta%20t%20%3D%204.1%20-%200.5%20%3D%203.6%20s)
now we have
![\Delta t = \frac{2v}{g}](https://tex.z-dn.net/?f=%5CDelta%20t%20%3D%20%5Cfrac%7B2v%7D%7Bg%7D)
![3.6 = \frac{2v}{9.8}](https://tex.z-dn.net/?f=3.6%20%3D%20%5Cfrac%7B2v%7D%7B9.8%7D)
![v = 17.64 m/s](https://tex.z-dn.net/?f=v%20%3D%2017.64%20m%2Fs)
so this is the speed at the top of flag pole
now we have
![v_f - v_i = at](https://tex.z-dn.net/?f=v_f%20-%20v_i%20%3D%20at)
![17.64 - v_i = (-9.8)(0.5)](https://tex.z-dn.net/?f=17.64%20-%20v_i%20%3D%20%28-9.8%29%280.5%29)
![v_i = 22.5 m/s](https://tex.z-dn.net/?f=v_i%20%3D%2022.5%20m%2Fs)
now the height of flag pole is given as
![H = \frac{v_f + v_i}{2}t](https://tex.z-dn.net/?f=H%20%3D%20%5Cfrac%7Bv_f%20%2B%20v_i%7D%7B2%7Dt)
![H = \frac{22.5 + 17.64}{2} (0.5)](https://tex.z-dn.net/?f=H%20%3D%20%5Cfrac%7B22.5%20%2B%2017.64%7D%7B2%7D%20%280.5%29)
![H = 10.05 m](https://tex.z-dn.net/?f=H%20%3D%2010.05%20m)
Answer:
moment of inertia is 2.72 kg m²
Explanation:
given data
mass m = 10kg
height h = 4.5 m
radius r = 0.5 m
speed v = 6.5 m/s
to find out
moment of inertia
solution
we apply here conservation of energy
that is
mgh = 1/2 ×mv² + 1/2 × Iω²
here I is moment of inertia we find and
we know ω = Velocity / radius = 6.5 / 0.5 = 13
and g = 9.8
so put here all these value
10 (9.8) 4.5 = 1/2 ×(10)(6.5)² + 1/2 × I(13)²
441 = 211.25 + 1/2 × I( 169 )
I = 2.72
so moment of inertia is 2.72 kg m²
1 nanowatt = 1 nanojoule/sec
1 watt = 1 joule/sec
10 watts = 10 joules/sec
100 watts = 100 joules/sec
742.914 watts = 742.914 joules/sec
1,000 watts = 1,000 joules/sec
10,000 watts = 10,000 joules/sec
100,000 watts = 100,000 joules/sec
1 megawatt = 1 megajoule/sec
1 gigawatt = 1 gigajoule/sec
1 petawatt = 1 petajoule/sec
We don't care what frequency the transmission is using,
or who their morning DJ is.
Answer:
option b is correct..................