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3 years ago

A regular polygon has angkes of size 150° each.how many side has the polygon

Physics

1 answer:

emmasim [6.3K]3 years ago

5 0

Answer: 12

Explanation:

ıf each interior is 150 degrees, then each exterior angle is 180–150 or 30 degrees. Hence the polygon has 360/30 = 12 sides

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A flat polished area is turned through 15 degrees. If the angle of incidence is 20 degrees, what is the angle between the incide

Ilya [14]

Answer:

Explanation:

Angle of rotation of the flat polished surface $\theta$ = 15°

angle of incidence i = 20°

Since the polished surface is turned at an angle of 15°, the angle of reflection

r = 2 $\theta$ (Note that the angle of rotation only have effect of the angle of reflection)

r = 2*15 = 30°

The angle between the reflected ray and the incident ray will be equal to the sum of the angle of incidence and the angle of reflection i.e i+r

The angle between the reflected ray and the incident ray = 20°+ 30° = 50°

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4 years ago

A 4kg block slides freely across a rough surface such that the block slows down with an acceleration of −1.25 m/s2 . What is the

Sophie [7]

Answer:

The coefficient of kinetic friction between the block and the surface is 0.127.

Explanation:

Given that,

The mass of a block, m = 4 kg

The acceleration of the block, a = -1.25 m/s²

We need to find the coefficient of kinetic friction between the block and the surface. The force of friction is given by :

$F=\mu mg\\\\ma=\mu mg\\\\\mu=\dfrac{a}{g}\\\\\mu=\dfrac{1.25}{9.8}\\\\\mu=0.127$

So, the coefficient of kinetic friction between the block and the surface is 0.127.

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3 years ago

A dam is a structure built across a river to hold back the river's water. The flow of water through a dam is controlled by gates

Bess [88]

Potential is the first blank and kinetic is the second blank.

This should be correct

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3 years ago

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a 282 kg bumper car moving right at 3.50 m/s collides with a 155 kg bumper car moving 1.88 m/s left. afterwards, the 282 kg car

Vaselesa [24]

The momentum of the 155 kg car afterwards is 469.7 kg m/s to the right

Explanation:

We can solve the problem by using the law of conservation of momentum: the total momentum of the system is conserved before and after the collision, so we can write:

$p_i = p_f\\m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2$

where:

$m_1 = 282 kg$ is the mass of the bumper car

$u_1 = 3.50 m/s$ is the initial velocity of the bumper car (we take the right as positive direction)

$v_1 = 0.800 m/s$ is the final velocity of the bumper car

$m_2 = 155 kg$ is the mass of the second bumper car

$u_2 = -1.88 m/s$ is the initial velocity of the second car (moving to the left)

$v_2$ is the final velocity of the second car

Solving for $v_2$ ,

$v_2 = \frac{m_1 u_1+m_2 u_2 - m_1 v_1}{m_2}=\frac{(282)(3.50)+(155)(-1.88)-(282)(0.800)}{155}=3.03 m/s$

where the positive sign means the direction is to the right.

And now we can find the momentum of the 155 kg afterwards, which is

$p_2 = m_2 v_2 = (155)(3.03)=469.7 kg m/s$ (to the right)

Learn more about momentum:

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3 years ago

What’s happening to the car’s motion?

ExtremeBDS [4]

Answer:

It returned to where it had started at the end of the trip

Explanation:

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3 years ago

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A regular polygon has angkes of size 150° each.how many side has the polygon​

A regular polygon has angkes of size 150° each.how many side has the polygon