<span>5.3 cm/s
This is a matter of conservation of momentum. Since there's no mention of the puck rebounding, I will consider this to be a totally non-elastic collision. So, let's determine the starting momentum of the system.
Goalie is at rest, so his momentum is 0.
Puck is moving at 30.00 m/s with a mass of 0.16 kg, so:
30.00 m/s * 0.16 kg = 4.8 kg*m/s
So the starting momentum is 4.8 kg*m/s moving towards the goal. After the collision, the puck and goalie will have the same momentum. So figure out the mass of the new system:
90.00 kg + 0.16 kg = 90.16 kg
And divide the system momentum by the system mass:
4.8 kg*m/s / 90.16 kg = 0.053238687 m/s
Finally, round to the least precise datum, so the result to 2 significant figures is 0.053 m/s, or 5.3 cm/s.</span>
Let the beam is of length L
Now the stress on both the end is same
now we can say that torque on the beam due to two forces must be zero
also we know that stress at both ends are same
Now from two equations we have
solving above equation we have
<em>so the load is placed at distance 0.4L from the end of 12 mm^2 area</em>
The membership rose among the baptist and methodists.
The resultant force is 8N
Given that mass is 2kg , v= 40m/s, u =20m/s and we need to calculate resultant force
F=ma
m is given
so for a
v-u/t=a { first equation of motion }
40-20/4= 4
so a=4
F = ma =2*4 = 8N
The difference between the forces that are acting on an object as part of a system is known as the resultant force.
v = u + at is the first equation of motion. Here, v denotes the end speed, u the starting speed, an acceleration, and t the passage of time. The first equation of motion is provided by the velocity-time relation, which may be used to calculate acceleration.
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