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3 years ago

What the suns mass in scientific notation????

Physics

2 answers:

Allushta [10]3 years ago

6 0

Explanation:

In scientific notation the Sun's mass is: =1.989 x 10 ^30 kg

Gala2k [10]3 years ago

6 0

Answer:

I think in scientific notation the Sun's mass becomes: <u>M Sun = 1.989 x 10 30 kg.</u> The number above the ten, called the power of ten or exponent, stands for the number of decimal places. If it is positive, as in the mass of the Sun, the decimal places are in front of the decimal point.

I hope this help you!:)

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a projectile is launched horizontally from a height of 65 meters with an initial horizontal speed of 35 meters pre second. what

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A projectile is launched horizontally from a height of 65 meters with an initial horizontal speed of 35 meters pre second. projectile's horizontal speed after it has fallen 25 meters is 35 m/s.

<h3>what is speed ?</h3>

Speed is measured as the ratio of distance to the time in which the distance was covered. Speed is a scalar quantity as it has only direction and no magnitude.

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Uniform speed is an uniform speed when the object covers equal distance at equal time intervals, variable speed is defined as when the object covers a different distance at equal intervals of times.

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1 year ago

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Little Susie is enjoying a nice spherical lollipop. She sucks the lollipop in such away that the circumference decreases by 1 ce

Brums [2.3K]

Answer:

-50 cm^3/min

Explanation:

The volume of the lollipop is given by

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To find how fast the volume changes, we need to find the rate of change of the volume, which is given by its derivative with respect to time:

$\frac{dV}{dt}=4\pi r^2 \frac{dr}{dt}$ (1)

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dr/dt is the rate of change of the radius

We know that the circumference is

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and it decreases by 1 cm per minute, so

$\frac{dC}{dt}=2\pi \frac{dr}{dt}=-1$ (cm/min)

from which we find dr/dt:

$\frac{dr}{dt}=-\frac{1}{2\pi}$

Substituting into (1),

$\frac{dV}{dt}=4\pi r^2 \frac{1}{2\pi}=-2r^2$ (cm^3/min)

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$\frac{dV}{dt}=-2(5)^2=-50$ (cm^3/min)

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To solve the problem, we must know the heat capacity of ice and water.

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Answer:

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