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otez555 [7]
2 years ago
7

Prove that the conjecture is false by providing a counter example.

Mathematics
1 answer:
Bas_tet [7]2 years ago
6 0

Answer:

Any negative number would be a counterexample.

Step-by-step explanation:

Since negative numbers get smaller as you multiply them by a larger number, this would prove this conjecture false.

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Simplify the expression (2y+1)-4y^2+2
Katena32 [7]

Answer:

-4y^2+2y+3

Step-by-step explanation:

(2y+1)-4y^2+2

2y+1-4y^2+2

-4y^2+2y+1+2

-4y^2+2y+3

5 0
2 years ago
Read 2 more answers
This is due today, please help!!! I will give brainliest.
WINSTONCH [101]

Answer:

Step 1, all the exponents are increased by 4

Step-by-step explanation:

The first incorrect step occurred in Step 1, where all the exponents were increased by 4.

This is mathematically incorrect due to exponential rules. When distributing exponents inside parentheses, we have to multiply the existing exponents inside the parentheses by the exponent outside the parentheses.

For example, (x²)³ is not x²⁺³, but rather, x⁽²⁾⁽³⁾.

We multiply the exponents instead of adding them together.

Therefore, the correct Step 1 should multiply all the variables' exponents by 4.

Steps 2 and 3 are correct since we do add the exponents when multiplying exponents with the same base, and we do subtract exponents with the same base when dividing.  

6 0
3 years ago
A quadrilateral with vertices at A(4, –4), B(4, –16), C(12, –16), and D(12, –4) has been dilated with a center at the origin. Th
erastova [34]
I think the answer is 3, because D(12;-4) and D' is (36;-12). Then 36/12=3, -12/-4=3
(I hope it's true)!!! :)
6 0
3 years ago
Read 2 more answers
The table shows how the number of sit-ups marla does each day has changed over time. at this rate how many sit-ups will she do o
DENIUS [597]
The number of situps form an AP with first term (a) = 17 and common difference (d) = 4

Tn = a + (n - 1)d
T12 = 17 + (12 - 1) x 4 = 17 + 11(4) = 17 + 44 = 61

Therefore, she will do 61 situps on day 12.
5 0
3 years ago
Read 2 more answers
Please help with this I am completely stuck on it
vaieri [72.5K]

Answer:

f(x)=\sqrt[3]{x-4} , g(x)=6x^{2}\textrm{ or }f(x)=\sqrt[3]{x},g(x)=6x^{2} -4

Step-by-step explanation:

Given:

The function, H(x)=\sqrt[3]{6x^{2}-4}

Solution 1:

Let f(x)=\sqrt[3]{x}

If f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}, then,

\sqrt[3]{g(x)} =\sqrt[3]{6x^{2}-4}\\g(x)=6x^{2}-4

Solution 2:

Let f(x)=\sqrt[3]{x-4}. Then,

f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}\\\sqrt[3]{g(x)-4}=\sqrt[3]{6x^{2}-4} \\g(x)-4=6x^{2}-4\\g(x)=6x^{2}

Similarly, there can be many solutions.

7 0
3 years ago
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