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zysi [14]
4 years ago
11

. Two waves that have the same wavelengths and amplitudes are traveling in opposite directions on a string. If each wave has a s

peed of 10 m/s and there are moments when the string is not moving, what is the wavelength of the waves if the time between each moment that the string is flat is 0.5 s?
Physics
1 answer:
anastassius [24]4 years ago
7 0

Answer:

10m

Explanation:

Since Given frequency f= 1/t

and velocity ν=10 m/s

We know ν=λf

λ= ν/f

​ = 10/1/0.5

=5m

Since both the waves are similar but moves in opposite direction its total wavelength of the wave will be 10 m

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erica [24]

Answer:

The magnitude of the magnetic field at the origin is 2.56\times 10^{-6}\ T.

Explanation:

Given :

50-A wire is in the x-z plane and is 5 m from the z axis.

Also , 40-A wire is in the y-z plane and is 4 m from the z axis.

Now , since both the wire are perpendicular to each other .

Therefore , magnetic field are also perpendicular to each other .

Magnetic field at origin due to wire 1 is :

B_1=\dfrac{\mu_oI_1}{2\pi R_1}\\\\B_1=\dfrac{(50)\mu_o}{2\pi( 5)}\\\\B_1=\dfrac{5\mu_o}{\pi}

Magnetic field at origin due to wire 2 is :

B_2=\dfrac{\mu_oI_2}{2\pi R_2}\\\\B_2=\dfrac{(40)\mu_o}{2\pi( 4)}\\\\B_2=\dfrac{4\mu_o}{\pi}

Now , therefore net magnetic field is :

B=\sqrt{B_1^2+B_2^2}\\\\B=\sqrt{(\dfrac{5\mu_o}{\pi})^2+(\dfrac{4\mu_o}{\pi})^2}\\\\B=\dfrac{\sqrt{41}\mu_o}{\pi}

Putting value of \mu_o=4\pi \times 10^{-7}\ H/m

We get ,

B=\sqrt{41}\times 4\times 10^{-7}\\B=2.56\times 10^{-6}\ T

Therefore, the magnitude of the magnetic field at the origin is 2.56\times 10^{-6}\ T.

5 0
3 years ago
In which list below do the experimental steps appear in the order in which they are done?
fgiga [73]
The answer is B . You begin with a purpose for the lab, then hypothesize on what you believe will happen. Next, follow the procedures. This is always the last step, Anatoly did. Reflect upon you hypothesis, did the lab support or disprove your hypothesis. Include observations you have made. Identify errors.
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3 years ago
A 9800-N automobile is pushed along a level road by four students who apply a total forward force of 600 N. Neglecting friction,
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Answer:

c).  a = 0.60 m/s^2

Explanation:

As we know that weight of the automobile is given here

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W = mg

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now from Newton's law

F = ma

600 = 1000 a

a = \frac{600}{1000}

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4 0
3 years ago
A man swings a bucket on a 120-cm rope with a tangential speed of 4.5 m/s. If the magnitude of the centripetal force is 25 N, wh
Paraphin [41]

Answer:

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Explanation:

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3 years ago
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Answer:

Electrical energy is answer

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hope it helps

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