An electric dipole consists of a particle with a charge of 6 x 10⁻⁶ c at the origin and a particle with a charge of –6 x 10⁻⁶ c on the x axis at x = 3 x 10⁻³ m. Its dipole moment is 18 x 10⁻⁹ Cm
Dipole moment of a dipole is dependent on the charge of the dipole and the distance between the two charges.
Electric Dipole consists of two charges which are equal and opposite in charge i.e. positive and negative charges.
Given,
Dipole moment, p = ?
Charge, q = 6 x 10⁻⁶C
Distance between charges, d = 3 x 10⁻³ m
Dipole moment (p) is given by:
p = charge x distance between the two charges
p = 6 x 10⁻⁶ x 3 x 10⁻³ Cm
p = 18 x 10⁻⁹ Cm
The dipole moment for the given charge configuration is 18 x 10⁻⁹ Cm
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Answer:
35.7 m
Explanation:
Let


We have to find the distance between Joe's and Karl'e tent.


Substitute the values then we get




Because vertical component of B lie in IV quadrant and y-inIV quadrant is negative.
By triangle addition of vector






Hence, the distance between Joe's and Karl's tent=35.7 m
Had to look for the options and here is my answer. What happens when the fluid discharge of an air-operated reciprocating pump is shut, this will cause the pump to OVERSTROKE. Overstroke happens when the engine is switching in a normally-closed manner.
Answer:
Radiation
Explanation:
The fire from the burning house is not directly touching the house. Also not convection because there is not water involved
Answer:
a

b

Explanation:
Generally the force of attraction between this two irons is mathematically represented as
![F = \frac{k * [Q_{Li} ] * [Q_{O} ] }{ r^2}](https://tex.z-dn.net/?f=F%20%3D%20%20%5Cfrac%7Bk%20%2A%20%20%5BQ_%7BLi%7D%20%20%5D%20%2A%20%5BQ_%7BO%7D%20%20%5D%20%20%7D%7B%20r%5E2%7D)
Here k is known as the proportionality constant with value 
substituting -2 for
i.e the charge on oxygen , +1 for
i.e the charge on Lithium and
for r
So


Generally the force of repulsion will be the magnitude but different direction to the force o attraction
So Force of repulsionn is
