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riadik2000 [5.3K]
3 years ago
10

What kind of energy involves the flow of charged particles?

Physics
1 answer:
Citrus2011 [14]3 years ago
3 0

Answer:

Electrical energy is answer

Explanation:

hope it helps

Mark me as brainliest plz.

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A 62 kg rock climber falls off the wall at the gym. Immediately before she hits the padded floor, her velocity is 7.9 m/s, 15° a
Kisachek [45]

Answer:

Explanation:

Given

mass of climber= 62 kg

velocity of climber before it hits=7.9 m/s at an angle of 15^{\circ} from vertical

therefore change in momentum in vertical direction is

\Delta P=m(v_i-v_f)

\Delta P=62\left ( 7.9cos15-(7.9cos15)\right )

\Delta P=2\times \62\times 7.9cos15=946.22 N.s

there is no change in horizontal momentum

and impulse=change in momentum

F.dt=946.22

F=\frac{946.22}{0.75}=1.261 kN

For non padded floor

F=\frac{946.22}{0.25}=3748.88 =3.748 kN

5 0
3 years ago
It takes 6s for a stone to fall from the top of a building to the ground calculate i.the height of the building ii.the speed of
omeli [17]

Answer:

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Explanation:

5 0
3 years ago
two objects were lifted by machine one object had a massive 2 kg it was lifted at a speed of 2 m/s the other had a massive 4 kg
rosijanka [135]
Kinetic energy =(1/2) (mass) (speed²)

First object:  KE = (1/2) (2 kg) (2m/s)² =  4 joules during the lift.

Second object:  KE = (1/2) (4kg) (3 m/s)² = 18 joules during the lift.

The second object has more kinetic energy while it's being lifted
than the first object has while it's being lifted. Once they reach their
final heights and stop, neither object has any kinetic energy. 
8 0
4 years ago
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lukranit [14]

Answer:

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7 0
3 years ago
A ball was dropped from a height of 10 feet. Each time it hits the ground, it bounces 4/5 of its previous height. Find the total
Shtirlitz [24]

Answer:

d = 90 ft

Explanation:

As we know that after each bounce it reaches to 4/5 times of initial height

so we can say

h_2 = \frac{4}{5}h

so the distance covered is given as

d = h + 2(\frac{4}{5}h) + 2(\frac{4}{5})^2h + 2(\frac{4}{5})^3h........

here we know that

h = 10 feet

d = h + 2(\frac{4}{5}h)(1 + \frac{4}{5} + (\frac{4}{5})^2 + ...........)

d = 10 + 2(\frac{4}{5}(10))(\frac{1}{1 - \frac{4}{5}})

d = 90 ft

8 0
3 years ago
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