<span> The </span>rate<span> of </span>pressure decreases with an increase in altitude<span> is not </span>constant<span>. Rather, </span>pressure decreases<span> rapidly near Earth's surface and more gradually at greater heights. </span>
Answer:
A= 148.92 m/s²
Explanation:
Given that
U(x,y) = (6.00 )x² - (3.75 )y ³
m= 0.04 kg
Now force in the x-direction
Fx= - dU/dx
U(x,y) = (6.00 )x² - (3.75 )y ³
dU/dx= 12 x
When x=0.4 m
dU/dx= 12 x 0.4 = 4.8
So we can say that
Fx= - 4.8 N
From Newtons law
F= m a
- 4.8 = 0.04 x a
a = -120 m/s²
Acceleration in x direction ,a = -120 m/s²
In y -direction
F= - dU/dy
U(x,y) = (6.00 )x² - (3.75 )y ³
dU/dy = 0 - 3.75 x 3 y²
When y = 0.56 m
dU/dy = - 3.75 x 3 x 0.56 x 0.56
dU/dy = - 3.52
So we can say that force in y -direction
F= 3.52 N
F= m a'
3.52 = 0.04 x a'
a'=88.2 m/s²
acceleration in y direction is 88.2 m/s²
The resultant acceleration
A= 148.92 m/s²
Answer:
b. Projectiles A & B have the same likelihood of breaking the glass since they have the same initial momentum
.
c. Projectile A has the greater likelihood of breaking the glass since its momentum change is larger.
Explanation:
for option b, the two projectiles have the same initial mass and velocity, hence they posses the same amount of momentum that if sufficient enough could break the glass.
for option c, projectile A changes direction, maintaining the same speed v. Its momentum changes from from mv to -mv, since its speed changed direction.
the difference in momentum becomes
Δp = -mv - mv = -2mv
this is twice the initial momentum.
projectile B changes momentum from mv to 0
Δp = 0 - mv = -mv.
this is half of the final momentum of projectile A.
Also we know that force is proportional to to the rate of change of momentum, which is greater in projectile A, therefore projectile A impacts more force on the glass. Projectile A therefore has the greater likelihood of breaking the glass since its momentum change is larger.
We know, I = F.Δt
As Δt is increased to 4 times, then, F would decrease to 4 times, in order to keep that impulse constant.
In short, Your force will change to 1/4th of it's initial value
Hope this helps!
