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Rus_ich [418]
3 years ago
12

Granola

Mathematics
1 answer:
Semenov [28]3 years ago
4 0

Answer:

1/8 : 1/2

Step-by-step explanation:

Is that the right answer? I’m not sure lol I don’t remember

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What is the value of n 9 times 27+2 times31-28
Kay [80]
9•27+2•31-28= ? Is that what you are asking?
8 0
3 years ago
In college​ basketball, a shot made from beyond a designated arc radiating about 20 ft from the basket is worth three points ins
denis-greek [22]

Answer:

a) By the Central Limit Theorem, the distribution would be approximately normal, with mean \mu = 0.45 and standard deviation s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.45*0.55}{100}} = 0.0497

b) 4.02 standard deviations below the mean.

c) Making 25 or less shots has a pvalue of -4.02. Z-scores lower than -2 are considered surprising, so yes, it would be surprising for him to make only 25 of these shots.

Step-by-step explanation:

To solve this question, we are going to need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For proportions, we have that the mean is \mu = p and the standard deviation is s = \sqrt{\frac{p(1-p)}{n}}

In this problem, we have that:

p = 0.45, n = 100

a)By the Central Limit Theorem, the distribution would be approximately normal, with mean \mu = 0.45 and standard deviation s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.45*0.55}{100}} = 0.0497

b)This is Z when X = 0.25.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.25 – 0.45}{0.0497}

Z = -4.02

4.02 standard deviations below the mean.

c) Making 25 or less shots has a pvalue of -4.02. Z-scores lower than -2 are considered

surprising, so yes, it would be surprising for him to make only 25 of these shots.

3 0
2 years ago
A toy box has 6 faces.There are square there are 12 edges and 8 vertices.Identify the shape of the toy box.
xxTIMURxx [149]

Answer:

A cube or a cuboid.

Step-by-step explanation:

A cube or a cuboid is a three dimensional shape that has

12 edges, 8 corners or vertices, and 6 faces.

The difference between a cube and cuboid is that a cube has all edges equal which makes every face a square while a cuboid has two square faces and four rectangular faces.

6 0
2 years ago
Y=-(5)^2=-100 how do I do that
Leona [35]
All you have to use is pemdas and keep y by itself
7 0
3 years ago
00:00
lidiya [134]

Answer:

4\frac{3}{8} yards of wood

Step-by-step explanation:

The correct question is Hakim is making birdhouses. Each birdhouse uses  7 /8 yard of wood. What is the total length of wood Hakim will need to build 5 birdhouses?

Answer: Given that the amount of wood need to produce one bird house is 7/8 yard, for 5 birdhouse, the amount of wood needed would be 5 times the number needed for one birdhouse. It is given by:

Amount of wood needed for 5 birdhouse = 5 × amount of wood for 1 birdhouse

Amount of wood needed for 5 birdhouse = 5 × 7/8 yards = 35/8 = 4\frac{3}{8} yards of wood

6 0
3 years ago
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