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svetoff [14.1K]
3 years ago
10

A converging lens focuses a set of light rays entering the lens on one side parallel to its axis to a single focal point on the

opposite side of the lens. if the principal rays emitted from a single point on an object all intersect at a single point after passing through a converging lens, then this intersection point helps in determining the location and size of a real image of the object. the most useful principal rays for converging lenses are the following:
Physics
1 answer:
Vladimir79 [104]3 years ago
7 0

1)The P ray is directed parallel to the axis of the lens. It emerges from the lens directed toward the focal point on the side of the lens opposite the object.


2) The M ray is directed toward the midpoint of the lens. It emerges from the lens unchanged in direction.


3) The F ray is directed toward the focal point on the same side of the lens as the object. It emerges from the lens directed parallel to the lens axis.


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A planet has a period of revolution about the Sun equal to and a mean distance from the Sun equal to R .T^2 varies directly as _
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T² caries directly as R³ .

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As the train in the image moves to the right which person hears the train horn at a lower pitch?
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B. C would be your answer
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Suppose you exert a 400-N force on a wall but the wall does not move. The work you are doing on the wall is : unknown, because t
Ilya [14]

Answer:

W = 0 :The work done on the wall is zero,because the wall is not moving

Explanation:

Work theory

Work is the product of a force applied to a body and the displacement of the body in the direction of this force.

W= F*d Formula (1)

W: Work (Joules) (J)

F: force applied (N)

d=displacement of the body (m)

The work is positive (W+) if the force goes in the same direction of movement.

The work is negative (W-)if the force goes in the opposite direction to the movement

Data

F= 400-N

d= 0

Problem development

We apply formula (1) to calculate the work done on the wall:

W= 400*0

W=0

6 0
3 years ago
The mass of the Earth is 6 × 1024 kg, the mass of the Moon is 7 × 1022 kg, and the center-to-center distance is 4 × 108 m. How f
Karolina [17]

Answer:

The center of mass of the Earth–Moon system is 4.613 × 10⁶ m from center of the Earth.

Explanation:

Let the reference point be the center of the Earth

X_{Cm = \frac{M_eX_e +M_mX_m}{M_e+M_m}

Where;

Xcm is the distance from center of the Earth =?

Me is the mass of the Earth = 6 × 10²⁴ kg

Xe is the center mass of the Earth = 0

Mm is the mass of the moon = 7 × 10²² kg

Xm is the center mass of the moon =  4 × 10⁸ m

X_{Cm = \frac{M_eX_e +M_mX_m}{M_e+M_m} =  \frac{M_e(0) +M_mX_m}{M_e+M_m} = \frac{ M_mX_m}{M_e+M_m}}\\\\X_C_m = \frac{7 X 10^{22}*4X10^8}{6X10^{24}+7X10^{22}} =\frac{28 X10^{30}}{607X10^{22}}\\\\  X_C_m = 4.613 X10^6 m

Therefore, the center of mass of the Earth–Moon system is 4.613 × 10⁶ m from center of the Earth.

8 0
3 years ago
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