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Soloha48 [4]
3 years ago
5

There are clouds forming over Florida. The temperatures in the clouds and in the air are above freezing. Which form of precipita

tion do you expect Florida to get and why?
Physics
1 answer:
PtichkaEL [24]3 years ago
6 0

The type of precipitation expected to occur in Florida is "Rain" when the temperatures of air and clouds are above freezing point.

<u>Explanation:</u>

Under certain conditions, water droplets get freezes due to low temperatures. However, if the temperature of the air beneath the cloud is higher than the freezing point 32°F (0°C), the frozen start to meltdown due to high temperature and falls as raindrops on the surface of the earth. Hence Rain form of precipitation is expected to occur in Florida when the temperature of the cloud and air is above freezing.

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A ball is thrown w a speed of 30m/s at an angle of 10. When is the vertical component of the velocity equal to zero
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Now the vertical velocity of the ball thrown at an angle 10° is given as

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A 2.45-kg frictionless block is attached to an ideal spring with force constant 355 N/m. Initially the spring is neither stretch
ANTONII [103]

Answer:

A.    A = 0.913 m

B.    amax = 132.24m/s^2

C.    Fmax = 324.01N

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When the block is moving at the equilibrium point , its velocity is maximum.

A. To find the amplitude of the motion you use the following formula for the maximum velocity:

v_{max}=A\omega          (1)

vmax = maximum velocity = 11.0 m/s

A: amplitude of the motion = ?

w: angular frequency = ?

Then, you have to calculate the angular frequency of the motion, by using the following formula:

\omega=\sqrt{\frac{k}{m}}           (2)

k: spring constant = 355 N/m

m: mass of the object = 2.54 kg

\omega = \sqrt{\frac{355N/m}{2.45kg}}=12.03\frac{rad}{s}

Next, you solve the equation (1) for A and replace the values of vmax and w:

A=\frac{v}{\omega}=\frac{11.0m/s}{12.03rad/s}=0.913m

The amplitude of the motion is 0.913m

B. The maximum acceleration of the block is given by:

a_{max}=A\omega^2 = (0.913m)(12.03rad/s)^2=132.24\frac{m}{s^2}

The maximum acceleration is 132.24 m/s^2

C. The maximum force is calculated by using the second Newton law and the maximum acceleration:

F_{max}=ma_{max}=(2.45kg)(132.24m/s^2)=324.01N

It is also possible to calculate the maximum force by using:

Fmax = k*A = (355N/m)(0.913m) = 324.01N

The maximum force exertedbu the spring on the object is 324.01 N

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