Answer:
The 3rd graph
Explanation:
A free body diagram is a diagram which shows all the forces acting on an object.
The problem asks us to find the free body diagram of block A, so we must find all the forces acting on block A.
We have 3 forces acting on block A in total:
- The force of gravity (its weight), which pushes the block downward (in the diagram, it is the force represented with 
- The tension in the rope 1, which pulls block A upwards: this force is represented with 
- The tension in the rope 2, due to the weight of block 2, which pulls block A downwards: this force is represented with 
Based on the direction of these 3 forces, the correct diagram is the 3rd one.
Answer:
θ = cos^(-1) (-A/B)
Explanation:
The image of the reauktant forces A & B are missing, so i have attached it.
Now, from the attached image, we will see that;
Angle between A and B is θ
Also;
A = Bcos(180° − θ)
Now, in trigonometry, we know that;
cos(180° − θ) = -cosθ
Thus;
A = -Bcosθ
cosθ = -A/B
Thus;
θ = cos^(-1) (-A/B)
Answer:
sin 30° = 
Multiply each side by 25 to cancel the 25 under 
(25)· sin 30° =
Multiply everything on the left side.
12.5 
= vertical velocity component.
I attached a picture, I hope it helps.
Answer: flow = 1600 ml/min
Hi!
This problem si solved using Poiseuille law, which predicts the flow φ of a viscous fluid through a tube:
We can calculate the ratio of initial (1) and final (2) flow. As we keep the same length, and viscosity, and pressure gradient the ratio is:
(100% increase in radius)
= 1600 ml/min
Answer:
I believe it is the same as before-Electrical energy is transformed into heat and light energy.
Explanation:
Hope this helps'-'
